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erica [24]
3 years ago
11

There are 13 sixth grade classrooms at LMMS. Each class has about 28 students.

Mathematics
1 answer:
Stels [109]3 years ago
6 0

Answer:

364 students

Step-by-step explanation:

multiply 13 by 28

You might be interested in
3x - y = 0<br> 2x - y = 1
9966 [12]
Answer: See below

Explanation:
Solve this system of equation using elimination method:

3x - y = 0
2x - y = 1
________
3x - y = 0
-1(2x - y = 1)
_________
3x - y = 0
-2x + y = -1
_________
X = -1

We know that x = -1 now let’s plug it in the one of the equation to find y:

2x - y = 1
2(-1) - y = 1
-2 - y = 1
-y = 3
y = -3

8 0
3 years ago
In XYZ, XY=XZ<br> Find the length of XY of XYZ if XY=2a, YZ=3a+1, andXZ=5a-12
lorasvet [3.4K]

Answer: XY = 8

Step-by-step explanation:

The diagram of the triangle XYZ is shown in the attached photo.

XY=XZ. This means that two sides of the triangle are equal. Two angles are also equal. It means that the triangle XYZ is an isosceles triangle.

Since XY=XZ, then

2a = 5a - 12

Subtracting 2a from both sides of the equation,

2a - 5a = 5a - 12 - 5a

-3a = -12

a = -12/-3

a = 4

Therefore, the length of XY is 2a = 2×4 = 8

5 0
2 years ago
The length of some fish are modeled by a von Bertalanffy growth function. For Pacific halibut, this function has the form L(t) =
Dafna1 [17]

Answer:

a) L'(t) = 34.416*e^(-0.18*t)

b) L'(0) = 34 cm/yr , L'(1) =29 cm/yr , L'(6) =12 cm/yr

c) t = 10 year                                          

Step-by-step explanation:

Given:

- The length of fish grows with time. It is modeled by the relation:

                                   L(t) = 200*(1-0.956*e^(-0.18*t))

Where,

L: Is length in centimeter of a fist

t: Is the age of the fish in years.

Find:

(a) Find the rate of change of the length as a function of time

(b) In this part, give you answer to the nearest unit. At what rate is the fish growing at age: t = 0 , t = 1, t = 6

c) When will the fish be growing at a rate of 6 cm/yr? (nearest unit)

Solution:

- The rate of change of length of a fish as it ages each year  can be evaluated by taking a derivative of the Length L(t) function with respect to x. As follows:

                             dL(t)/dt = d(200*(1-0.956*e^(-0.18*t))) / dt

                             dL(t)/dt = 34.416*e^(-0.18*t)

- Then use the above relation to compute:

                            L'(t) = 34.416*e^(-0.18*t)

                            L'(0) = 34.416*e^(-0.18*0) = 34 cm/yr

                            L'(1) = 34.416*e^(-0.18*1) = 29 cm/yr

                            L'(6) = 34.416*e^(-0.18*6) = 12 cm/yr

- Next, again use the derived L'(t) to determine the year when fish is growing at a rate of 6 cm/yr:

                             6 cm/yr = 34.416*e^(-0.18*t)

                             e^(0.18*t) = 34.416 / 6

                             0.18*t = Ln(34.416/6)

                             t = Ln(34.416/6) / 0.18

                             t = 10 year

7 0
3 years ago
A scale mode of a building is 8 in. by 12 in. The scale is 1 in:15 ft. What are the dimensions of the actual building? (*you nee
VikaD [51]

Answer:

120 ft by 180 ft

Step-by-step explanation:

If every inch is 15 feet multiply 8 inches by 15 and then 12 by 15 to get your dimensions

15 * 8 = 120

15 * 12 = 180

120 x 180 feet

Convert to inches if needed.

1440 inches by 2160 inches

6 0
2 years ago
Find the sum.<br> 13(9−6m)+14(12m−8) =
allochka39001 [22]

Answer:

5+90m

Step-by-step explanation:

117 - 78m + 168m - 112


117- 112 = 5

-78m + 168m= 90m


5+90m

7 0
3 years ago
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