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4 years ago

How do I plot this???

Mathematics

1 answer:

Free_Kalibri [48]4 years ago

6 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have the inequality

$x+2.5 > 7$

Solve for x

Subtract 2.5 both sides

$x+2.5-2.5 > 7-2.5$

$x> 4.5$

The solution is the interval (4.5,∞)

All real numbers greater than 4.5

In a number line the solution is the shaded area at right of x=4.5 (open circle because the number 4.5 is not included)

see the attached figure to better understand the problem

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Help me to answer now ineed this <br> Please...

Vera_Pavlovna [14]

ANSWER TO QUESTION 1

$\frac{\frac{y^2-4}{x^2-9}} {\frac{y-2}{x+3}}$

Let us change middle bar to division sign.

$\frac{y^2-4}{x^2-9}\div \frac{y-2}{x+3}$

We now multiply with the reciprocal of the second fraction

$\frac{y^2-4}{x^2-9}\times \frac{x+3}{y-2}$

We factor the first fraction using difference of two squares.

$\frac{(y-2)(y+2)}{(x-3)(x+3)}\times \frac{x+3}{y-2}$

We cancel common factors.

$\frac{(y+2)}{(x-3)}\times \frac{1}{1}$

This simplifies to

$\frac{(y+2)}{(x-3)}$

ANSWER TO QUESTION 2

$\frac{1+\frac{1}{x}} {\frac{2}{x+3}-\frac{1}{x+2}}$

We change the middle bar to the division sign

$(1+\frac{1}{x}) \div (\frac{2}{x+3}-\frac{1}{x+2})$

We collect LCM to obtain

$(\frac{x+1}{x})\div \frac{2(x+2)-1(x+3)}{(x+3)(x+2)}$

We expand and simplify to obtain,

$(\frac{x+1}{x})\div \frac{2x+4-x-3}{(x+3)(x+2)}$

$(\frac{x+1}{x})\div \frac{x+1}{(x+3)(x+2)}$

We now multiply with the reciprocal,

$(\frac{(x+1)}{x})\times \frac{(x+2)(x+3)}{(x+1)}$

We cancel out common factors to obtain;

$(\frac{1}{x})\times \frac{(x+2)(x+3)}{1}$

This simplifies to;

$\frac{(x+2)(x+3)}{x}$

ANSWER TO QUESTION 3

$\frac{\frac{a-b}{a+b}} {\frac{a+b}{a-b}}$

We rewrite the above expression to obtain;

$\frac{a-b}{a+b}\div {\frac{a+b}{a-b}}$

We now multiply by the reciprocal,

$\frac{a-b}{a+b}\times {\frac{a-b}{a+b}}$

We multiply out to get,

$\frac{(a-b)^2}{(a+b)^2}$

ANSWER T0 QUESTION 4

To solve the equation,

$\frac{m}{m+1} +\frac{5}{m-1} =1$

We multiply through by the LCM of $(m+1)(m-1)$

$(m+1)(m-1) \times \frac{m}{m+1} + (m+1)(m-1) \times \frac{5}{m-1} =(m+1)(m-1) \times 1$

This gives us,

$(m-1) \times m + (m+1) \times 5}=(m+1)(m-1)$

$m^2-m+ 5m+5=m^2-1$

This simplifies to;

$4m-5=-1$

$4m=-1-5$

$4m=-6$

$\Rightarrow m=-\frac{6}{4}$

$\Rightarrow m=-\frac{3}{2}$

ANSWER TO QUESTION 5

$\frac{3}{5x}+ \frac{7}{2x}=1$

We multiply through with the LCM of $10x$

$10x \times \frac{3}{5x}+10x \times \frac{7}{2x}=10x \times1$

We simplify to get,

$2 \times 3+5 \times 7=10x$

$6+35=10x$

$41=10x$

$x=\frac{41}{10}$

$x=4\frac{1}{10}$

Method 1: Simplifying the expression as it is.

$\frac{\frac{3}{4}+\frac{1}{5}}{\frac{5}{8}+\frac{3}{10}}$

We find the LCM of the fractions in the numerator and those in the denominator separately.

$\frac{\frac{5\times 3+ 4\times 1}{20}}{\frac{(5\times 5+3\times 4)}{40}}$

We simplify further to get,

$\frac{\frac{15+ 4}{20}}{\frac{25+12}{40}}$

$\frac{\frac{19}{20}}{\frac{37}{40}}$

With this method numerator divides(cancels) numerator and denominator divides (cancels) denominator

$\frac{\frac{19}{1}}{\frac{37}{2}}$

Also, a denominator in the denominator multiplies a numerator in the numerator of the original fraction while a numerator in the denominator multiplies a denominator in the numerator of the original fraction.

That is;

$\frac{19\times 2}{1\times 37}$

This simplifies to

$\frac{38}{37}$

Method 2: Changing the middle bar to a normal division sign.

$(\frac{3}{4}+\frac{1}{5})\div (\frac{5}{8}+\frac{3}{10})$

We find the LCM of the fractions in the numerator and those in the denominator separately.

$(\frac{5\times 3+ 4\times 1}{20})\div (\frac{(5\times 5+3\times 4)}{40})$

We simplify further to get,

$(\frac{15+ 4}{20})\div (\frac{(25+12)}{40})$

$\frac{19}{20}\div \frac{(37)}{40}$

We now multiply by the reciprocal,

$\frac{19}{20}\times \frac{40}{37}$

$\frac{19}{1}\times \frac{2}{37}$

$\frac{38}{37}$

5 0

3 years ago

What's .34 as a fraction

kondaur [170]

0.34 = 34/100
34/100 = 17/50

6 0

3 years ago

Read 2 more answers

How many permutations are possible for 13 objects taken 6 at a time?

Anarel [89]

Answer:

1,235,520

Step-by-step explanation:

13P6 = 13!/(13-6)! = 13·12·11·10·9·8 = 1,235,520

There are 13 ways to choose the first object, 12 ways to choose the second, 11 ways to choose the third, and so on. The 6th object can be chosen 8 ways.

The total number of permutations is the product of all these ways:

13·12·11·10·9·8 = 1,235,520

7 0

3 years ago

4,412.096 rounded to the nearest hundredth.

Mkey [24]

We remember that when we round a decimal, we look the number to the right to the one we want to round (in this case, as we want to round to the nearest hundredth, we look at the thousandth position).

0. If the number ,is greater or equal than 5, we round up, (this is, we add 1 number to the position).

1. If the number, is less than 5, we round down, (we leave the same number)

In our exercise, we look at the thousandth position, which is 6. And as it is bigger than 5, we add 1 to the 9 (which is the hundredth position):

We obtain 10, but then as we can't put 10 on a digit, we add 1 to the tenth, and we obtain:

$4,412.10$

Thus, 4,412.096 rounded to the nearest hundredth is 4,412.1.

8 0

2 years ago

The shipping box has a length of 30 inches and a height of 6 inches. How wide should the box be to fit the 36-inch bat? Show and

irinina [24]

Answer:

width = 18.97 inches

Step-by-step explanation:

To find the smallest width of the box to fit the bat, we need to put the bat in the diagonal of the box.

The diagonal of the box is given by:

diagonal^2 = length^2 + width^2 + height^2

Then, using the diagonal = 36 inches, length = 30 inches and height = 6 inches, we have:

36^2 = 30^2 + width^2 + 6^2

1296 = 900 + width^2 + 36

width^2 = 360

width = 18.97 inches

6 0

3 years ago