Answer:
To determine the nature of roots of quadratic equations (in the form ax^2 + bx +c=0) , we need to calculate the discriminant, which is b^2 - 4 a c. When discriminant is greater than zero, the roots are unequal and real. When discriminant is equal to zero, the roots are equal and real.
Answer:
is
Step-by-step explanation:
so I calculated this and I got a fraction
I got 64/135
Answer:
Cosec <F = 73/55
Step-by-step explanation:
In ΔEFG, the measure of ∠G=90°, GF = 48, EG = 55, and FE = 73. What ratio represents the cosecant of ∠F?
First you must know that;
Cosecant <F = 1/sin<F
Given
∠G=90°, GF = 48, EG = 55, and FE = 73.
ED ,= hyp = 73
EG = opp = 55*side facing <F
Using DOH CAH TOA
Sin theta = opp/hyp
Sin <F= 55/73
Reciprocate both sides
1/sinF = 73/55
Cosec <F = 73/55
Answer:
Here you go.Hope this help!!
The solution to your problem is as follows:
The tangent line passes through (4,-6), so x = 4 when y = -6
=> f(4) = -6
The tangent line will have a constant gradient.
gradient is m = (-6 - 9)/(4 - 10) => 5/2
Equation is y - 9 = (5/2)(x - 10)
=> y - 9 = (5/2)(x-10)
<span>i.e. y = (5/2)(x-10) + 9
</span> y = (5/2)x - 25 + 9 = y = (5/2)x - 16
Now, f '(x) = dy/dx = 5/2
so, f '(4) = 5/2....i.e. gradient is 5/2 whatever the value of x.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
