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olga55 [171]
3 years ago
11

What is the solution to the system of equations? y = 1/3x – 10 2x + y = 4

Mathematics
2 answers:
kolezko [41]3 years ago
5 0
The solution is (6, -8) (solved by graphing with Desmos.com/calculator)
serg [7]3 years ago
3 0

Answer:

x=6, y=8

Step-by-step explanation:

First, we can put the sytem of equations in standard form, it holds that

y-\dfrac{1}{3}x=-10\\\\\\y+2x=4

then, we can substract the second equation from the first equation to get that

(\dfrac{-1}{3}-2)x=-10-4\quad\Rightarrow\quad \dfrac{-7}{3}x=-14\\\\\quad\Rightarrow\quad x=6

Finally, we use this result in the first equation to get that

y-\dfrac{1}{3}\cdot 6=-10\quad\Rightarrow\quad y-2=-10\quad\Rightarrow y=8

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The points A(3, 4), B(3, -2), C(-5, -2), and D(-5, 4) form rectangle ABCD. Which point is halfway between A and B?
Dmitriy789 [7]
 Answer:  " (3,1)  is the point that is halfway between <em>A</em> and <em>B</em>. " 
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Explanation:
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We know that there is a "straight line segment" along the y-axis between
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 1)  Points A, B, C, and D form a rectangle;  AND:
 
 2) We are given the coordinates for each of the 4 (FOUR points); AND:
 
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  We know that the x-coordinate of this "half-way" point is three.

We can look at the "y-coordinates" of BOTH "Point A" and "Point B".
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which are "4" and "-2",  respectively.

Now, let us determine the MAGNITUDE of the number of points along the "y-axis" between "y = 4" and y = -2 . 

The answer is:  "6" ;  since, from y = -2 to 0 , there are 2 points, or 2 "units" from y = -2 to y = 0 ;  then, from y = 0 to y = 4, there are 4 points, or 4 "units".

Adding these together,  2 + 4 = 6 units.
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So, the "half-way" point would be 1/2  of  6 units, or 3 units.
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So, from y = -2 to y = 4 ;  we could count 3 units between these points, along the "y-axis".   Note, we could count "2" units from  "y = -2"  to "y = 0". 
Then we could count one more unit, for a total of 3 units;  from y = 0 to y = 1;  and that would be the answer (y-coordinate of the point).
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Alternately, or to check this answer, we could determine the "halfway" point along the "y-axis" from "y = 4" to "y = -2" ; by counting 3 units along the "y-axis" ; starting starting with "y = 4" ; note:  4 - 3 = 1 ; which is the "y-coordinate" of our answer; that is: "y = 1" ;  and the same y-coordinate we have from the previous (aforementioned) method above.
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We know the "x-coordinate" is "3" ; so the answer:
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   " (3,1)  is the point that is halfway between <em>A</em> and<em> B </em>." 
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