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3 years ago

What two numbers add to 7 and multiply to 10

Mathematics

2 answers:

OlgaM077 [116]3 years ago

8 0

The numbers are five and two

GalinKa [24]3 years ago

3 0

The answer to your question is 5 and 2

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PLEASE HELP WILL GIVE BRAINLIEST Abby purchased 4 2/5 gallons of paint to paint 4 walls of a room in her house. the cost of one

natima [27]

Answer:

Cost to paint 4 walls of a room = $24.20

Cost of painting 3 walls of a room =$18.15

Step-by-step explanation:

(a) Abby purchased 4 2/5 gallons of paint to paint 4 walls of a room in her house.

$4\frac{2}{5}gallons \ of \ paint = \frac{4*5+2}{5} =\frac{22}{5}$

1 gallon cost = 5.50

So 22/5 gallons cost = $\frac{22}{5} * 5.5= 24.20$

Cost to paint 4 walls of a room = $24.20

(b)cost of painting 4 walls of a room = $24.20

cost of painting 1 wall of a room = $\frac{24.20}{4} =6.05$

Cost of painting 3 walls of a room = 6.05 * 3= $18.15

7 0

3 years ago

The owner of a cattle ranch would like to fence in a rectangular area of 3000000 m^2 and then divide it in half with a fence dow

Reika [66]

If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l

now $\bf \begin{cases}
A=l\cdot w\\\\\
A=3000000\\
----------\\
3000000=l\cdot w\\\\
\frac{3000000}{w}=l
\end{cases}\qquad thus
\\\\\\
P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w}
\\\\\\
P=3w+6000000w^{-1}\\\\
-----------------------------\\\\
now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2}
\\\\\\
\textit{so the critical points are at }
\begin{cases}
0=w^2\\\\
0=\frac{3w^2-6000000}{w^2}
\end{cases}$

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

notice the $0=w^2\implies 0=w$ so. you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0

so.. check the critical points on the other

8 0

3 years ago

In a sample of 70 stores of a certain company, 62 violated a scanner accuracy standard. It has been demonstrated that the condi

uysha [10]

Answer:

We need at least 243 stores.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error of the interval is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$n = 70, p = \frac{62}{70} = 0.886$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Determine the number of stores that must be sampled in order to estimate the true proportion to within 0.04 with 95% confidence using the large-sample method.

We need at least n stores.

n is found when M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.886*0.114}}{n}}$