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2 years ago

The lin 2x - 3y = 4 does not passes through the point :

Mathematics

1 answer:

Ymorist [56]2 years ago

3 0

Answer:

The choose D (2, –1)

2x-3y=4 —> 3y=2X-4 —> y= 2/3x – 4/3

y=mx+b —> So ; m= 2/3 , b= - 4/3

y-intercept :(0, -4/3)

0=2/3x –4/3 —> 2/3x = 4/3 —> X=2

x-intercept ; (2,0)

By drawing a straight line from point 2 on the x-axis and point -4/3 on the y-axis, the points that are on the axis have been extracted, but the point (2,-1) is not on the axis . :)

I hope it helped you ^_^

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Pls help meh

san4es73 [151]

Answer:

7.1 (7.06 rounded to the tenth)

Step-by-step explanation:

The formula for Area of a Circle is: π·r²

R = Radius

π = pi, or 3.14

As long as you know the formula, this is easy!

In class, you may have already been told that the radius is <em>half </em>of the diameter.

1. Half of 3 ft is 1.5 ft.

2. Plug 1.5 in for r, in your calculator

3. Do the calculation, and you should come out to get 7.06858347058

4. Round it!

Finding area for a circle is satisfying, isn't it? xD

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2 years ago

Which equation has x=4 as the solution

erma4kov [3.2K]

(1) step by step below

5 0

3 years ago

Work out the estimate for the number of times both spinners land on the blue.

iris [78.8K]

Answer:

Step-by-step explanation:

probabilty of both being red= 0.5*0.6

total no of times spinners were spun = 84/(0.5*0.6) = 280

probabilty of both being blue= 0.5*0.4

Estimate = 0.5*0.4*280= 56

5 0

3 years ago

Please please please help and solve this with steps, much help needed thank you :) 20 points for this!

leonid [27]

Answer:

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

$\frac{dy}{dx}y=x^3+2x-5x+3$

$\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}$

$\mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)$

1. $\mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:$

$y'\:y=x^3+2x-5x+3$

2. $\mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}$

$yy'\:=x^3-3x+3$

$N\left(y\right)\cdot y'\:=M\left(x\right)$

$N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3$

3. $\mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1$

4. $\mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}$

5. $\mathrm{Simplify}$

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

7 0

3 years ago

Read 2 more answers

A storm moves at a rate of 8 miles per hour. It is 200 miles away from Freeport and headed directly for this town. The equation

Eduardwww [97]

Pls see answer below.

Step-by-step explanation:

In this case, our slope is -8. This means that every hour, the storm is getting closer to the town by 8 miles per hour.

Our y-intercept is 200, which means that its' initial position is 200 miles away from the town.

Hope this helped.

7 0

3 years ago