Answer:
Keyboard,speaker,scanner,mouse,printer and monitor
Explanation:
In computing, an input device is a piece of equipment used to provide data and control signals to an information processing system such as a computer or information appliance. Examples of input devices include keyboards, mouse, scanners, cameras, joysticks, and microphones.
import java.util.Scanner;
public class JavaApplication57 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("Enter two numbers:");
int num1 = scan.nextInt();
int num2 = scan.nextInt();
while (num1 <= num2){
if (num1 %2 == 0){
System.out.print(num1+" ");
}
num1+=1;
}
}
}
I hope this helps!
Answer: (C) A special service for current customers
Explanation:
The CRM is the customer relationship management that typically use by the banks for providing special type of services to the current customer. This is the way to attract various types of users or customers by providing some special type of offers.
According to the question, bank provide the credit card offers to the customer on the airline tickets so, it is beneficial for both the customer and for the bank as well.
Answer:
The correct answers are: (A) +/- 5V and (B) +/- 12V
Explanation:
First at all, the purpose of the power supply is transforming from AC (Alternating Current) to DC (Direct Current) for use this energy in chips and electronics devices that consume this type of power. Usually the most common DC voltage for electronics is 5V but in your CPU you also have other devices that might going to need more voltage like fan or hard drives thats ´s why 12V is an also an option. Now some other devices are going to need negative sources such -5V or -12V as well.
Answer:
Total Memory= 4 KB = 4096 bytes = 32768 bits
Explanation:
<em><u>1. Data lines are 8 From D0 to D7</u></em>
so
Total memory at single address locations is 8 bits.
<em><u>2. Address lines are 12 (A0 to A11)</u></em>
There are 12 address lines but 3 out 12 are for selction of chip or memory bank.
so only 9 pins are there to address the locations on one chip.
Total No. of address locations on single chip = 2^9 = 512 locations
as 1 location is 1 byte so total memory of single chip is 512 bytes.
<u><em>3. Total Memory Bank </em></u>
There are total 3 selection pins for memory bank.
so
Total chips = 2^3 = 8.
<em><u>4. Total Memory </u></em>
Total size of 1 chip = 512 bytes
Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb
<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>
