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3 years ago

What is the area of the composite figure whose vertices have the following coordinates?

Mathematics

2 answers:

Fofino [41]3 years ago

8 0

Answer:

60 square units

Step-by-step explanation:

We can use Pythagoras to solve this as appropriately projecting lines from any point will form a triangle. The vertical and horizontal lengths of which can be read of from the axis.

The distance between two points is √ ( x 1 − x 2 ) 2 + ( y 1 − y 2 ) 2

Let the distance between two points be

d i

Distance between points A and B

d 1 = √ [ 3 − ( − 3 ) ] 2 + [ 7 − 5 ] 2 d 1 = √ 36 + 4 = √ 2 2 × 10 = 2 √ 10

Distance between points B and C

d2 = √ [ 6 − 3 ] 2 + [ 7 − ( − 2 ) ] 2 d 2 = √ 9+ 81 = √ 3 2 × 10 = 3 √ 10

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Area = d 1 × d 2 = 2 √ 10 × 3 √ 10 = 60

YW :>

AveGali [126]3 years ago

6 0

Answer:

60 square units

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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So, our particular solution is $y_p= \frac{8}{3}x^3-8x^2+16x$ .

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$y''=\lambda^2e^{\lambda x}$

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$e^{\lambda x}(\lambda +\lambda^2)= 0$

$(\lambda +\lambda^2)= 0$

$\lambda (1+\lambda)= 0$

$\lambda =0$ and $\lambda)= -1$ .

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$y=y_p+y_h =\frac{8}{3}x^3-8x^2+16x+ C_1 + C_2e^{-x}$ .

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