The height of a cylinder is twice the radius of its base.
1 answer:
Let x represent radius of circle.
We have been given that the height of a cylinder is twice the radius of its base. So height of cylinder would be .
Now we will use volume of cylinder formula to our given problem.
, where,
r = Radius of base of cylinder,
h = Height of cylinder.
Upon substituting our given values, we will get:
Therefore, our required volume expression would be .
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Answer: Lattice parameter, a = (4R)/(√3)
Step-by-step explanation:
The typical arrangement of atoms in a unit cell of BCC is shown in the first attachment.
The second attachment shows how to obtain the value of the diagonal of the base of the unit cell.
If the diagonal of the base of the unit cell = x
(a^2) + (a^2) = (x^2)
x = a(√2)
Then, diagonal across the unit cell (a cube) makes a right angled triangle with one side of the unit cell & the diagonal on the base of the unit cell.
Let the diagonal across the cube be y
Pythagoras theorem,
(a^2) + ((a(√2))^2) = (y^2)
(a^2) + 2(a^2) = (y^2) = 3(a^2)
y = a√3
But the diagonal through the cube = 4R (evident from the image in the first attachment)
y = 4R = a√3
a = (4R)/(√3)
QED!!!
