A share of stocks gained 12 points, then lost 114 points, and then gained 218 points. Find the overall change in its value.
1 answer:
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A) The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle. You know the length of the gift shop, l = 20x + 24. You know the width, w = 36x - 20. Plug those expressions into the equation for area of a rectangle and multiply/foil:
The expression for the area of the gift shop is
.
B) The equation for the perimeter of the gift shop is P = 2(l+w), where l = length and w = width. Plug your values for l and w into this equation:
The expression for the perimeter of the gift shop is 112x + 8
C) Since you know the perimeter is going to be 176 ft, that means P = 176. Plug that into the equation you found in part B, P = 112x + 8, and solve for x.
Once you solve for x, you can plug x into your equations for width and length to find the dimensions. x = 1.5, so:
1) L<span>ength = 20x+24 feet
</span>Length = 20(1.5) + 24 feet = 54 feet
2) Width = <span>36x-20 feet
Width = 36(1.5)-20 feet = 34 feet
Your dimensions are 54 feet (length) by 34 feet (width).</span>
The expression for the area of the gift shop is
B) The equation for the perimeter of the gift shop is P = 2(l+w), where l = length and w = width. Plug your values for l and w into this equation:
The expression for the perimeter of the gift shop is 112x + 8
C) Since you know the perimeter is going to be 176 ft, that means P = 176. Plug that into the equation you found in part B, P = 112x + 8, and solve for x.
Once you solve for x, you can plug x into your equations for width and length to find the dimensions. x = 1.5, so:
1) L<span>ength = 20x+24 feet
</span>Length = 20(1.5) + 24 feet = 54 feet
2) Width = <span>36x-20 feet
Width = 36(1.5)-20 feet = 34 feet
Your dimensions are 54 feet (length) by 34 feet (width).</span>
Since you're only asked the ordered pair of D'', it's much easier just to plot and reflect point D twice than to do that for all four points!
Remember that reflecting points is like putting a mirror at the line of reflection or flipping that point over at that line. The reflected point should be the same distance from the line of reflection as the original point.
1) Reflect D over the x-axis to get D'.
D is at (4,1). Draw a line that is perpendicular to the line of reflection and goes through D. D is as far from the line of reflection as D' should be on its other side (both are on that perpendicular line). Since D is 1 unit above the x-axis, that means D' is 1 unit below at (4, -1). See picture 1.
2) Reflect D' over <span>y=x+1 to get D''.
D' is at (4, -1). Draw </span>y=x+1 and the line perpendicular to it going through D''. D'' is the same distance from the line of reflection on the other side. See picture 2. D'' is at (-2, 5).
Answer: D'' is at (-2, 5)
Remember that reflecting points is like putting a mirror at the line of reflection or flipping that point over at that line. The reflected point should be the same distance from the line of reflection as the original point.
1) Reflect D over the x-axis to get D'.
D is at (4,1). Draw a line that is perpendicular to the line of reflection and goes through D. D is as far from the line of reflection as D' should be on its other side (both are on that perpendicular line). Since D is 1 unit above the x-axis, that means D' is 1 unit below at (4, -1). See picture 1.
2) Reflect D' over <span>y=x+1 to get D''.
D' is at (4, -1). Draw </span>y=x+1 and the line perpendicular to it going through D''. D'' is the same distance from the line of reflection on the other side. See picture 2. D'' is at (-2, 5).
Answer: D'' is at (-2, 5)