Using the arrangements formula, it is found that there are 24 ways for them to stand in line so that the youngest person is always first, and the oldest person is always last.
<h3>What is the arrangements formula?</h3>
The number of possible arrangements of n elements is given by the factorial of n, that is:

In this problem, we have that there are 6 people. The youngest person(Leslie) has to be first, while the oldest(Parvinis) has to be last, while the remaining 4 can be arranged, hence the number of ways for them to stand in line is given by:

More can be learned about the arrangements formula at brainly.com/question/24648661
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Answer:
X^5+3x^4+81x+ 243
Step by step:
X^4*x=x^5
X^4*3=3x^4
81*x=81x
81*3=243
Answer:
Algebra
Topics
How do you find the intercepts of x2y−x2+4y=0?
Algebra Graphs of Linear Equations and Functions Intercepts by Substitution
2 Answers
Gió
Mar 24, 2015
For the intercepts you set alternately x=0 and y=0 in your function:
and graphically:
Answer link
Alan P.
Mar 24, 2015
On the X-axis y=0
So
x2y−x2+4y=0
becomes
x2(0)−x2+4(0)=0
→−x2=0
→x=0
On the Y-axis x=0
and the original equation
x2y−x2+4y=0
becomes
(0)2y−(0)2+4y=0
→y=0
The only intercept for the given equation occurs at (0,0)
Answer link
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Number 2 is already a mixed number. But it says mixed number as a decimal. So -1 29/40 as a decimal is -1.725.
Answer:
The dimensions are x =20 and y=20 of the garden that will maximize its area is 400
Step-by-step explanation:
Step 1:-
let 'x' be the length and the 'y' be the width of the rectangle
given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is 2(x +y) = 80
x + y =40
y = 40 -x
now the area of the rectangle A = length X width
A = x y
substitute 'y' value in above A = x (40 - x)
A = 40 x - x^2 .....(1)
<u>Step :2</u>
now differentiating equation (1) with respective to 'x'
........(2)
<u>Find the dimensions</u>
<u></u>
<u></u>
40 - 2x =0
40 = 2x
x = 20
and y = 40 - x = 40 -20 =20
The dimensions are x =20 and y=20
length = 20 and breadth = 20
<u>Step 3</u>:-
we have to find maximum area
Again differentiating equation (2) with respective to 'x' we get

Now the maximum area A = x y at x =20 and y=20
A = 20 X 20 = 400
<u>Conclusion</u>:-
The dimensions are x =20 and y=20 of the garden that will maximize its area is 400
<u>verification</u>:-
The perimeter = 2(x +y) =80
2(20 +20) =80
2(40) =80
80 =80