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pychu [463]
3 years ago
12

Which point lies on the circle centered at the origin with radius V5?

Mathematics
1 answer:
7nadin3 [17]3 years ago
6 0

Answer:

2, _/21

Step-by-step explanation:

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Use the following data set and a separate piece of paper to make a line plot that will help you to answer questions 2-7. (6, 4,
Montano1993 [528]
Hello? If you don't know, mode means the most occurring number. And in the data, the number 6 has occurred four times. Which means that the answer is 6.
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An isosceles trapezoid is a quadrilateral with two congruent legs and a pair of parallel bases. Prove the base angles of an isos
Firdavs [7]
Check the picture below.

now, we know that the slanted legs are congruent, since it's an isosceles trapezoid, we also know that the bases are the parallel sides, so, the "altitude" or distance from those bases are the same length, for each of those triangles in the picture.

now, the bases are parallel, that means the altitude segment is perpendicular to the base, the longest side at the bottom, so, we end up with a right-triangle that has a Hypotenuse and a Leg, equal to the other triangle's.

thus, by the HL theorem for right triangles, both of those triangles are congruent, and if the triangles are congruent, all their sides are also, including the ones on the base.

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3 years ago
A rectangular piece of paper has a width that is 3 inches less than its length. It is cut in half along a diagonal to create two
saul85 [17]

Answer:

I think the answer is right.isn't The rectangle width 8 and length 11 inches

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3 years ago
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When 5 times a number is added to 45 the answer is the sm of 85 and 140 what is the number
zimovet [89]

Hello.

First, let the number be r.

5 times r is written like this:

\rm{5r}

Now, add 45:

\mathrm{5r+45}

Now, the sum of 5r+45 is equal to the sum of 85 and 140:

\mathrm{5r+45=85+140}

In order to solve this equation, we need to add 85 and 140:

\mathrm{5r+45=225}

Now, subtract 45 from both sides:

\mathrm{5r+45-45=225-45}

\mathrm{5r=225-45}

\mathrm{5r=180}

The last step is to divide both sides by 5:

\mathrm{r=36}

Therefore, the answer is

\rm{r=36}

I hope it helps.

Have a nice day.

\boxed{imperturbability}

8 0
2 years ago
If you select one card at random from a standard deck of 52 cards, what is the probability that the card is a five AND a club?
horsena [70]

Probability is expressed as

number of favorable outcomes/number of total outcomes

The number of cards in a deck is 52(total outcomes)

Recall, there is only 1 five of clubs in a deck of cards(favorable outcomes)

Thus, the probability that the card is a five AND a club is 1/52

4 0
1 year ago
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