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uranmaximum [27]
3 years ago
11

What is the solution to this inequality?

%20-%204%29" id="TexFormula1" title=" - 6 x - 4 \geqslant - 2( x - 4)" alt=" - 6 x - 4 \geqslant - 2( x - 4)" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Gekata [30.6K]3 years ago
4 0

Answer:

x≤-3

Step-by-step explanation:

the answer is x‹-3.

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(-3)=−22−3+11<br> EVALUATE
konstantin123 [22]

Answer:

− 3 = − 14

Step-by-step explanation:

Hope this helps !

8 0
3 years ago
What is the value of f(x) = 36x when x =1/2
ivann1987 [24]
The value of f(x) is 18 because when there is 1/2, think about half (i think like that). so what is the half of 36? 18.
3 0
3 years ago
2^5/4=2^5/2^a=2^b=c please help
Rudiy27
You just need to equate the expressions to find the values for a,b and c. First, let's settle that 2^5/4=8, and 8 is 2^3. Also, an important tool here is the indicie rule:
\frac{ a^{m} }{ a^{n} } = a^{m-n}
1st expression: 2^5/4=8
2nd expression: It tells us that 2^5/2^a=2^3 (I know that this equals to 8 as all the expressions are equal therefore is the same as our first expression). Using the indicie law, this means that a=2
3rd expression: 2^b must equal to 8 as well, so b=3
4th expression: c=8 as all of the other expressions we have figured out equal to 8 
So a=2, b=3 and c=8
6 0
3 years ago
JABDBS- what does X equal?
krek1111 [17]

Answer:

x = 5

Step-by-step explanation:

Given

\frac{20}{16} = \frac{x}{4} ( cross- multiply )

16x = 80 ( divide both sides by 16 )

x = 5

7 0
3 years ago
Please help! what is the polar equation r = -5 theta in parametric form?<br><br> thank you!
Rudiy27

Use these equations when converting polar equations to parametric equations:

x=r\cos\theta

y=r\sin\theta

We know that r=5\theta, so substitute that into both equations for x and y.

x=5\theta\cos\theta

y=5\theta\sin\theta

Now, replace \theta with any variable that you want to represent the parametric equations in. I'll use the standard variable, t

x=5t\cos t

y=5t\sin t

Thus, r=5\theta represented in parametric form is:

(x,y)=(5t\cos t, 5t \sin t)

Let me know if you need any clarifications, thanks!

~ Padoru

4 0
4 years ago
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