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3 years ago

Someone help me with this it's due tomorrow!!!!!!!!!!

Mathematics

1 answer:

Westkost [7]3 years ago

8 0

Answer:

Dang

Your teacher is evil haha

You might be interested in

55% of the 880 students at julian's school are male. How many male students are in julian's school?

Oliga [24]

Answer:

448

Step-by-step explanation:

55 Divided by 880 is 448

4 0

3 years ago

Can someone plz help me with this one problem plz!!! I WILL MARK BRAINLIEST!!!

Digiron [165]

Answer:

(1,6) , (2,7) , (3,8) , (4,9) , (5,10)

Step-by-step explanation:

Given equation: y = x + 5

when x = 1, y = 1 + 5 = 6

(1,6)

when x = 2, y = 7

(2,7)

when x = 3 , y = 8

(3,8)

when x = 4 , y = 9

(4,9)

when x = 5 , y = 10

(5,10)

4 0

2 years ago

Y − 16 = plzzz helpppp

chubhunter [2.5K]

Well it depends do u want it in rational form or fraction from or?

5 0

2 years ago

Hey! Can someone check my answers?

Andrew [12]

The greatest common factor is the biggest number taken from the values.

Q1. The answer is A. 5y^6

$20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}$
Since $x^{a}* x^{b} =x^{a+b}$ , then $x^{9}= x^{3}* x^{6}$

Back to our expression:
$4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+ 5y ^{6}*1=5 y^{6} (4y ^{3} +1)$
The greatest common factor is thus $5 y^{6}$

Q2. The answer is D. 12xy^2

$12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}$
We will use the rule $x^{a}* x^{b} =x^{a+b}$ to factorise the exponents:
$12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)$
The greatest common factor is thus $12xy^{2}$

3 0

3 years ago

Pls help me I only have 2 minutes left winner gets brainliest

devlian [24]

Answer:

i think it was about 5000.

Step-by-step explanation:

7 0

2 years ago