Answer:

Step-by-step explanation:
The formula to find the area and circumference of a circle is:

<em>*</em><em>no</em><em>te that pi is 3.14*</em><em> </em>Therefore the area is:

Therefore the circumference is:

Answer:
square root of 6: 2.449
Step-by-step explanation:
Answer:
Step-by-step explanation:
|-3| means the absolute value of -3. The absolute value sign means the number without its negative. The dictionary says: the magnitude of a real number without regard to its sign.
So |-3|= 3 and -3= -3
Calculate the circumference of the full circle:
circumference = PI x diameter = 3.14 x 20 = 62.8 inches
the arc length is 160 degrees of the full circle
divide 160 by 360 (full circle) and multiply by the circumference:
160/360 x 62.8 = 27.9 inches
Answer:
2744 pennies.
Step-by-step explanation:
Let x represent the number of pennies Al have initially.
We have been given that Al agreed to give 3/7 of his pennies to Bev, so number of pennies Bev will get would be
.
We are also told that Bev gave 3/7 of what she got from Al to Carl, so number of pennies that Carl will get would be
.
Further, Carl gave 3/7 of what he got from Bev to Dani, so number of pennies that Dani will get would be
.
We are also told that Dani received 216 pennies. Now, we will equate 216 to
and solve for x as shown below:
Therefore, Al have 2744 pennies initially.