Answer:
ĐÉO OKF
Step-by-step explanation:
Answer:
teri is tired
Step-by-step explanation:
from running
Let (x,y) be an arbitrary point on the circle.
Then d = √[x-3)2 + (y-0)2] = √[x2 - 6x + 9 + y2]
Since x2 + y2 = 1, y2 = 1-x2.
So, d = √[x2 - 6x + 9 + 1 - x2]
d = √(-6x+10)
Domain: x is the x-coordinate of a point on the circle centered at (0,0) with radius 1. So, -1≤x≤1.
But, for d to be defined, we need -6x+10 ≥ 0. So, x ≤ 5/3 (True for all x in [-1,1]).
Domain = [-1,1]
Range: -1 ≤ x ≤ 1 So, 6 ≥ -6x ≥ -6
16 ≥ -6x+10 ≥ 4
4 ≥ √(-6x+10) ≥ 2 That is, 2 ≤ d ≤4
Range: [2,4]
Step-by-step explanation:
K - Kitchen
b - Bedroom
l - Library
k = 4b
l = 14b
k + b + l = 817 pounds
4b + b +14b = 817 pounds
19b = 817 lbs
b = 817/19 pounds
b = 43 pounds
Since k = 4b
k = 4 * 43 pounds
k = 172 pounds
5 - 7 = - 2 ;
- 2 - 7 = - 9 ;
-9 - 7 = -16 ;
"common difference" d is - 7 ;
The n-th term of an arithmetic sequence is of the form <span>an = a1 + (n – 1)d ;
</span>a50 = 5 + 49 × ( - 7 ) = 5 - 343 = - 338;
