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kondor19780726 [428]
3 years ago
13

1500Tsh was divided amoung juma,anna and rose in ratio of 2:3:5 respectively.find how much each got?​

Mathematics
1 answer:
ASHA 777 [7]3 years ago
4 0

Answer:

juma->300

anna->450

rose->750

Step-by-step explanation:

j : a : r

2: 3:5

2+3+5=10

10u-> 1500

1u->150

2u->300

3u->450

4u->750

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Answer:If you are using a calculator, simply enter 770×100÷70, which will give you the answer.

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Based o the sample results what percent of the opulation prefers reading a hard copy i fht e digital copy is 4, the hard copy is
Lisa [10]

Based on the sample results of the population the percentage of population that  prefers reading a hard copy i fht e digital copy is 4, the hard copy is 21 and n equas 25 is 84%

Step-by-step explanation:

From the above question  we know that .

<u>Total number of population, n = 25</u>

Number of people who prefer to read a digital copy = 4

Number of people who prefer to read a hard copy = 21

As per the question we need to  find out the percentage  of population who prefer to read hard copy.

So we use the formula

<u>Percent of population preferring hard copy = Hard copy/Total*100</u>

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3 years ago
Please help on the area for 7 8 9 please all i need help is
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The area of the equilateral, isosceles and right angled triangle are 12.6mm², 9.61in² and 16.81yds² respectively.

<h3>What is the area of the equilateral, isosceles and right angle triangle?</h3>

Note that:

The area of an Equilateral triangle is expressed as A = ((√3)/4)a²

Where a is the dimension of the side.

The area of an Isosceles triangle is expressed as A = (ah)/2

Where a is the dimension of the base and h is the height.

The area of a Right angled triangle is expressed as A = (ab)/2

Where a and b is the dimension of the two sides other than the hypotenuse.

For the Equilateral triangle.

Given that;

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A = ((√3)/4)(5.4mm)²

A = ((√3)/4)( 29.16mm² )

A = 12.6mm²

Area of the Equilateral triangle is 12.6mm²

For the Isosceles triangle.

Given that;

  • Base a = 3.4in
  • Slant height b = 5.9in
  • height h = ?
  • Area A = ?

The height h is the imaginary line drawn upward from the center of a.

First, we calculate the height using Pythagorean theorem

x² = y² + z²

Where x = b = 5.9in, y = a/2 = 3.4in/2 = 1.7in, and z = h

(5.9in)² = (1.7in)² + h²

34.81in² = 2.89in² + h²

h² = 34.81in² - 2.89in²

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h = √31.92in²

h = 5.65in

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A = (ah)/2

A = (3.4in × 5.65in )/2

A = 19.21in²/2

A = 9.61in²

Area of the Isosceles triangle is 9.61in².

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Given that;

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A = (ab)/2

A = ( 8.2yds × 4.1yds)/2

A = ( 33.62yds²)/2

A = 16.81yds²

Area of the Right angled triangle is 16.81yds²

Therefore, the area of the equilateral, isosceles and right angled triangle are 12.6mm², 9.61in² and 16.81yds² respectively.

Learn more about Pythagorean theorem here: brainly.com/question/343682

#SPJ1

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