Answer:
The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)
Step-by-step explanation:
Given that:
Mean = μ = 150
SD = σ = 12
Let x1 be the first data point and x2 the second data point
We have to find the z-scores for both data points
x1 = 135
x2 = 167
So,
And
We have to find area to the left of both points then their difference to find the probability.
So,
Area to the left of z1 = 0.1056
Area to the left of z2 = 0.9207
Probability to score between 135 and 167 = z2-z1 = 0.9027-0.1056 = 0.8151
Hence,
The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)
Answer: you have to substitute them into the equation
Step-by-step explanation:
example: x = 2y - 6
lets say you test 4/5 so it would be 4 = 2(5) - 6
this equals 4 = 10 - 6 which is true
so that is how you test to see if the equation is right
remember the first number goes to "x" and the second one goes to y
hope this helps mark me brainliest if you can
Answer:
3 < x < 17
Step-by-step explanation:
Given 2 sides then the possible range of the third side x is
difference of 2 sides < x < sum of 2 sides , that is
10 - 7 < x < 10 + 7
3 < x < 17
Answer:
$1.56
Step-by-step explanation:
125.32 : 80.5 = 1.55677 => ~1.56$
Answer:
The snow from each event melts off before the next accumulation and no snow is on the ground at your scheduled time of observation. The total snowfall for that reporting 24-hour day is the sum of the three separate snow squalls, 6.7 inches, even though the snow depth on your board at observation time was zero. Snow often melts as it lands. your welcome!
