Answer:
Probability [Both ball red without replacement] = 26 / 77
Step-by-step explanation:
Given:
Number of white ball in beg = 6 balls
Number of black ball in beg = 3 balls
Number of red ball in beg = 13 balls
Find:
Probability [Both ball red without replacement]
Computation:
Probability of first red ball = Number of red ball in beg / [Total balls in beg]
Probability of first red ball = 13 / [6 + 3 + 13]
Probability of first red ball = 13 / 22
Probability of Second red ball = Number of remaining red ball in beg / [Total balls in beg without replacement]
Probability of Second red ball = [13 - 1] / [6 + 3 + 12]
Probability of Second red ball = 12 / 21
Probability [Both ball red without replacement] = [Probability of first red ball][Probability of Second red ball]
Probability [Both ball red without replacement] = [13/22][12/21]
Probability [Both ball red without replacement] = 26 / 77
