F is 8 h is 2 hope that helpssss
Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:
8 cm and 9 cm
Step-by-step explanation:
In order to find out, you add both 8 and 9 together. If the sum is above/higher than the number 13, they can all be made into a triangle. 8+9 is 17 and 17 is higher than 13.
hope this helps!
