Answer:
Probability that component 4 works given that the system is functioning = 0.434 .
Step-by-step explanation:
We are given that a parallel system functions whenever at least one of its components works.
There are parallel system of 5 components and each component works independently with probability 0.4 .
Let <em>A = Probability of component 4 working properly, P(A) = 0.4 .</em>
<em>Also let S = Probability that system is functioning for whole 5 components, P(S)</em>
Now, the conditional probability that component 4 works given that the system is functioning is given by P(A/S) ;
P(A/S) = {Means P(component 4 working and system also working)
divided by P(system is functioning)}
P(A/S) = {In numerator it is P(component 4 working) and in
denominator it is P(system working) = 1 - P(system is not working)}
Since we know that P(system not working) means that none of the components is working in system and it is given with the probability of 0.6 and since there are total of 5 components so P(system working) = 1 -
.
Hence, P(A/S) =
= 0.434.
Answer:
Step-by-step explanation:
I always like to use the mean if I can. In this data set, it's probably not a very good idea. Too much weight is given to that 7.2 and the two 3.2s.
I would choose the median, because the mode is the same answer and that's a good enough reason for choosing anything. 2 out 3 isn't bad as they say in Baseball.
1) X=159
2) BCD=103
3) DCH=89
im pretty sure
Answer:
figure please...... I cant see the figure
6y = 24 -3x
divide both sides by 6.
y = (x)/2 +4