Answer:
108 degrees
Step-by-step explanation:
Given
Let the angles be A and B


Required
Find the larger angle
If both angles form linear pair, then the following relationship exist:

Substitute values for A and B

Collect Like Terms


Solve for x


Substitute 13.5 for x in







<em>Hence, the larger angle measures 108</em>
The function representing the number of ounces is:
2x - 3
Now, we are given the number of ounces = 7
Therefore:
2x - 3 = 7
We will solve this equation for x as follows:
2x-3 = 7
2x = 7 + 3
2x = 10
x = 5
Therefore, the number line representing this function will be the line having a solution ending at 5 (5 is included).
Therefore, the correct choice would be line B

:
feet
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EXPLANATION:</u></h2><h2><u>
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Given:
V = 19,200 feet³ volume of the sculpture
H = 36 feet height of the sculpture
a = ? side length of the square base
The formula for calculating the volume of a pyramid is:
V = B H / 3 ⇒ B = 3 V / H
B = 3 · 19,200 / 36 = 19,200 / 12 = 1,600
B = a²
a² = 1,600 ⇒ a = √1,600 = 40 feet
a = 40 feet
Hope It Helped!
<u>And Tell me if The answer is wrong. . .</u>
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<h2>
<u>Good Luck With Your Assignment!</u></h2><h2>
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Answer:
B. There is no solution.
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
- Solving systems of equations by graphing
Step-by-step explanation:
<u>Step 1: Define systems</u>
y = x + 9x + 5
y = -x + 11x + 29
<u>Step 2: Simplify systems</u>
y = 10x + 5
y = 10x + 29
<u>Step 3: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 10x + 5 = 10x + 29
- Subtract 10x on both sides: 5 ≠ 29
Here we see that 5 does not equal 29.
∴ The systems has no solutions.
<u>Step 4: Graph systems</u>
<em>Check the solution set (if applicable).</em>
We see that the 2 lines are parallel and will never intersect. Therefore, this proves that our systems has no solution.