F is a function. It takes inputs and then produces an output. The notation f(x) is saying more specifically that the function is taking an input x and producing the output f(x). For example, if you look at f(x)=x2, you can think that f is the "squaring function", with input x and outputs x2. You can think that "f" is like the name of the function. f1(x)=x2 f2(x)=6x+3 Above, you know which function I'm talking about if I say f2. But often, people will just call it as the function f2(x)

3 0

3 years ago

What's 50+20+15+35+15+5+20+15+5=?

topjm [15]

Answer:

180

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

Events a, b, and c in a sample space have p(a)=0.2, p(b)=0.4, and p(c)=0.1. find p(a ∪ b ∪

Julli [10]

If $A$ and $B$ are mutually independent, then $\mathbb P(A\cup B)=\mathbb P(A)+\mathbb P(B)$ and $\mathbb P(A\cap B)=0$ .

If $A$ and $C$ are independent, then $\mathbb P(A\cap C)=\mathbb P(A)\cdot\mathbb P(C)$ . Ditto for $B$ and $C$ .

The inclusion/exclusion principle says that

$\mathbb P(A\cup B\cup C)=\mathbb P(A)+\mathbb P(B)+\mathbb P(C)-\mathbb P(A\cap B)-\mathbb P(A\cap C)-\mathbb P(B\cap C)+\mathbb P(A\cap B\cap C)$

Since $A$ and $B$ are mutually exclusive, their intersection is the empty set. It then follows that $A\cap B\cap C$ also is the empty set, so the last probability is also 0.

Plug in what we know:

$\mathbb P(A\cup B\cup C)=0.2+0.4+0.1-0-0.2\cdot0.1-0.4\cdot0.1+0$

$\implies\mathbb P(A\cup B\cup C)=0.64$

3 0

3 years ago

San R APOR is a right triangle. IF RO = 8, what is PO? mios 16

attashe74 [19]

Answer:

PQ = 16

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos60° = $\frac{1}{2}$ , then