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galben [10]
2 years ago
13

Find the area of the regular polygon. Give the answer to the nearest tenth.

Mathematics
1 answer:
gavmur [86]2 years ago
5 0

Answer:

\displaystyle 93,5\:in.^2 \approx A

Step-by-step explanation:

\displaystyle \frac{3\sqrt{3}}{2}a^2 = A \hookrightarrow \frac{3\sqrt{3}}{2}6^2 = A \\ \frac{3\sqrt{3}}{2}[36] = A; 54\sqrt{3}\:[or\:93,530743609...] \\ \\ \boxed{93,5 \approx A}

I am joyous to assist you at any time.

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Simplify the following expression.<br> 343 1/3<br> (Write your answer as an integer.)
aalyn [17]
343^1/3
=(7)^3*1/3 [ 3 and 3 are cancelled]
=7
4 0
3 years ago
Choose all the expressions that are equal to 7.6 ÷ 10. Please help me!
Mumz [18]

Answer:

a

Step-by-step explanation:

8 0
2 years ago
Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunne
Pavlova-9 [17]

Answer:

t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507  

p_v =P(t_{(15)}>1.507)=0.076

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

Step-by-step explanation:

1) Data given and notation

\bar X_{CTS}=2.35 represent the mean for the sample CTS

\bar X_{N}=1.83 represent the mean for the sample Normal

s_{CTS}=0.88 represent the sample standard deviation for the sample of CTS

s_{N}=0.54 represent the sample standard deviation for the sample of Normal

n_{CTS}=10 sample size selected for the CTS

n_{N}=7 sample size selected for the Normal

\alpha=0.01 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the group CTS is higher than the mean for the Normal, the system of hypothesis would be:

Null hypothesis:\mu_{CTS} \leq \mu_{N}

Alternative hypothesis:\mu_{CTS} > \mu_{N}

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{CTS}-\bar X_{N}}{\sqrt{\frac{s^2_{CTS}}{n_{CTS}}+\frac{s^2_{N}}{n_{N}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507  

P-value

The first step is calculate the degrees of freedom, on this case:

df=n_{CTS}+n_{N}-2=10+7-2=15

Since is a one side right tailed test the p value would be:

p_v =P(t_{(15)}>1.507)=0.076

We can use the following excel code to calculate the p value in Excel:"=1-T.DIST(1.507,15,TRUE)"

Conclusion

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

6 0
3 years ago
 
Amiraneli [1.4K]

Answer:

4

Step-by-step explanation:

bet

7 0
3 years ago
Read 2 more answers
A plastic bin contains red yellow and green keychains out of 350 keychains 10% or yellow off the remaining keychains three sets
pantera1 [17]

Answer:

The question is not comprehensive, the comprehensive question is:

A plastic bin contains red, yellow, and green key chains. Out of 350 key chains, 10% percent are yellow. Of the remaining key chains, 3/5 are green. How many red key chains are inside the bin?

There are 126 red key chains in the plastic bin

Step-by-step explanation:

The plastic bin contains keychains of red, yellow and green colours.

According to the question, the total keychains in the bin are 350.

10% of this keychains are yellow i.e. 10/100 × 350 = 35

Thus, 35 keychains are yellow in colour.

This means, we have 350 - 35 = 315 keychains consisting of red and green colours left.

The question further says that 3/5 of the remaining keychains (315) are green i.e. 3/5 × 315 = 945/5 = 189

Thus, there are 189 green keychains in the bin.

To get the number of red keychains in the plastic bin, we add the number of yellow and green keychains, and subtract the sum from the total keychains (350).

We have 35 (yellow) + 189 (green) = 224 yellow and green keychains.

Hence, red keychains = 350 (total keychains) - 224 (yellow and green)

= 126 red keychains

There are 126 keychains in the plastic bin.

4 0
3 years ago
Read 2 more answers
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