A. -f(1)=1,f(2)=2,f(n)=2f(n-1)f(n-2);n>2
Answer:
The pairs are (13,15) and (-15,-13).
Step-by-step explanation:
If n is an odd integer, the very next odd integer will be n+2.
n+1 is even (so we aren't using this number)
The sum of the squares of (n) and (n+2) is 394.
This means
(n)^2+(n+2)^2=394
n^2+(n+2)(n+2)=394
n^2+n^2+4n+4=394 since (a+b)(a+b)=a^2+2ab+b^2
Combine like terms:
2n^2+4n+4=394
Subtract 394 on both sides:
2n^2+4n-390=0
Divide both sides by 2:
n^2+2n-195=0
Now we need to find two numbers that multiply to be -195 and add up to be 2.
15 and -13 since 15(-13)=-195 and 15+(-13)=2
So the factored form is
(n+15)(n-13)=0
This means we have n+15=0 and n-13=0 to solve.
n+15=0
Subtract 15 on both sides:
n=-15
n-13=0
Add 13 on both sides:
n=13
So if n=13 , then n+2=15.
If n=-15, then n+2=-13.
Let's check both results
(n,n+2)=(13,15)
13^2+15^2=169+225=394. So (13,15) looks good!
(n,n+2)=(-15,-13)
(-15)^2+(-13)^2=225+169=394. So (-15,-13) looks good!
Answer:
One is 2 0's before the decimal point (100) and the other is 2 decimal places AFTER the decimal point (0.01)
Essentially, the question is asking us how many times do we multiply 0.01 to get 100? This will be how many times greater 100 is compared to 0.01
Lets move the decimal point 4 times to the right:
0.01
00.1
1.0
10.0
100.0
Step-by-step explanation:
If A and B are supplementary angles, then:
A+B=180º
In this case:
A=44º
44º+B=180º
B=180º-44º=136º
Anser: the measure of the other angle is 136º
