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Ber [7]
4 years ago
10

Inattentional blindness occurs when individuals do not observe certain objects or events because they are focused on something e

lse. please select the best answer from the choices provided t f
Computers and Technology
2 answers:
PSYCHO15rus [73]4 years ago
5 0
The answer is True have a good day
sergeinik [125]4 years ago
5 0
True, inattentional blindness can make a person temporarily blind. This happens when the attention of a person can no longer absorb more stimulus other than the activities being directly done. One way to fight this is to train the eyes using rewards.
You might be interested in
Complete function PrintPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 3, print "To
SVETLANKA909090 [29]

Answer:

<h2>Function 1:</h2>

#include <stdio.h> //for using input output functions

// start of the function PrintPopcornTime body having integer variable //bagOunces as parameter

void PrintPopcornTime(int bagOunces){

if (bagOunces < 3){ //if value of bagOunces is less than 3

 printf("Too small"); //displays Too small message in output

 printf("\n"); } //prints a new line

//the following else if part will execute when the above IF condition evaluates to //false and the value of bagOunces is greater than 10

else if (bagOunces > 10){

    printf("Too large"); //displays the message:  Too large in output

    printf("\n"); //prints a new line }

/*the following else  part will execute when the above If and else if conditions evaluate to false and the value of bagOunces is neither less than 3 nor greater than 10 */

else {

/* The following three commented statements can be used to store the value of bagOunces * 6 into result variable and then print statement to print the value of result. The other option is to use one print statement printf("%d",bagOunces * 6) instead */

    //int result;

    //result = bagOunces * 6;

    //printf("%d",result);

 printf("%d",bagOunces * 6);  /multiplies value of bagOunces  to 6

 printf(" seconds");

// seconds is followed with the value of bagOunces * 6

 printf("\n"); }} //prints a new line

int main(){ //start of main() function body

int userOunces; //declares integer variable userOunces

scanf("%d", &userOunces); //reads input value of userOunces

PrintPopcornTime(userOunces);

//calls PrintPopcornTime function passing the value in userOunces

return 0; }

Explanation:

<h2>Function 2:  </h2>

#include <stdio.h> //header file to use input output functions

// start of the function PrintShampooInstructions body having integer variable numCycles as parameter

void PrintShampooInstructions(int numCycles){

if(numCycles < 1){

//if conditions checks value of numCycles is less than 1 or not

printf("Too few."); //prints Too few in output if the above condition is true

printf("\n"); } //prints a new line

//else if part is executed when the if condition is false and else if  checks //value of numCycles is greater than 4 or not

else if(numCycles > 4){

//prints Too many in output if the above condition is true

printf("Too many.");

printf("\n"); } //prints a new line

//else part is executed when the if and else if conditions are false

else{

//prints "N: Lather and rinse." numCycles times, where N is the cycle //number, followed by Done

for(int N = 1; N <= numCycles; N++){

printf("%d",N);

printf(": Lather and rinse. \n");}

printf("Done.");

printf("\n");} }

int main() //start of the main() function body

{    int userCycles; //declares integer variable userCycles

   scanf("%d", &userCycles); //reads the input value into userCycles

   PrintShampooInstructions(userCycles);

//calls PrintShampooInstructions function passing the value in userCycles

   return 0;}

I will explain the for loop used in PrintShampooInstructions() function. The loop has a variableN  which is initialized to 1. The loop checks if the value of N is less than or equal to the value of numCycles. Lets say the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 1<2. So the program control enters the body of loop. The loop body has following statements. printf("%d",N); prints the value of N followed by

printf(": Lather and rinse. \n"); which is followed by printf("Done.");

So at first iteration:

printf("%d",N); prints 1 as the value of N is 1

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

1: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 2.

Now at second iteration:

The loop checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to true as N<numCycles  which means 2=2. So the program control enters the body of loop.

printf("Done."); prints Done after the above two lines.

printf("%d",N); prints 2 as the value of N is 2

printf(": Lather and rinse. \n");  prints : Lather and rinse and prints a new line \n.

As a whole this line is printed on the screen:

2: Lather and rinse.

Then the value of N is incremented by 1. So N becomes 2 i.e. N = 3.

The loop again checks if the value of N is less than or equal to the value of numCycles. We know that the value of numCycles = 2. So the condition evaluates to false as N<numCycles  which means 3>2. So the loop breaks.

Now the next statement is:

printf("Done."); which prints Done on the screen.

So as a whole the following output is displayed on the screen:

1: Lather and rinse.

2: Lather and rinse.

Done.

The programs along with their outputs are attached.

6 0
3 years ago
What is an example of constructive criticism for an employee who frequently arrives late?
aleksley [76]
I believe the correct answer is A
5 0
3 years ago
Read 2 more answers
IRQ 0 interrupt have _______________ priority<br> ? low<br> ? medium<br> ? highest<br> ? lowest
tekilochka [14]

Answer:

Highest

Explanation:

A interrupt request / IRQ is in which instructions are sent to Cpu and uses an interrupt handler to run distinct program . Hardware interrupts are used to manage occurrences such as obtaining modem or network card information, important presses, or mouse motions.

  • Interrupt request 0. – it is a system timer (can not be altered)
  • Interrupt request 1 – keyboard controller (can not be changed)
  • Interrupt request 2 – cascaded IRQ 8–15 signals (any device configured to use IRQ 2 will genuinely use IRQ 9)
  • Interrupt request 3 – serial port 2 controller
  • Interrupt request 4 –  serial port 1 controller
  • Interrupt request 5 –parallel port 2 and 3
  •  Interrupt request 6 - floppy disk controller
  •  Interrupt request 7 –parallel port 1. If a printer is not present, it is used for printers or for any parallel port. It can also possibly be shared with a secondary sound card with cautious port management.

As interrupt number increases priority level decreases, Priority level 0 is the highest priority level .

4 0
3 years ago
Write a program that calculates the amount of money the salesperson will earn from selling discount cards. java program
BaLLatris [955]

Answer:

import java.util.Scanner; public class Salesman2 {

public static void main(String[] args) { // TODO Auto-generated method stub double CommissionRate;

double TotalSales, Commission;

Scanner Read = new Scanner (System.in); System.out.println("Please enter total sales "); TotalSales=Read.nextDouble();

if (TotalSales<500)

CommissionRate=0.0;

else if (TotalSales>=500 && TotalSales <1000) CommissionRate=0.05;

else

CommissionRate=0.08;}

Commission = CommissionRate * TotalSales;

System.out.println("The Commision is: "+ Commission); }

}

}

4 0
3 years ago
Which girl is he baddest 1. Shawty 2.Lisa 3.Ashley
Ainat [17]

Answer:

. . . . . . . S H A W T Y.. . .. . .

3 0
3 years ago
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