Answer:
Option A: print("The total is %0.5f" % total)
Explanation:
To ensure the value is rounded to a precision of 5 digits, we have to create a formatted string which is %0.5f. The <em>.5</em> denotes five decimal places and <em>f </em>refers to float data type.
Next, we use the <em>%</em> operator again and followed with the variable <em>total</em>. The % is used as a string modulo operator that will interpolate the value held by the the variable <em>total </em>in the formatted string that we create previously. The interpolated value will be rounded to 5 decimal places. For example, if
total = 256.786789
The output will be 256.78679
Answer:
It’s OSI. also your question cut off lol
4.
3.
1.
5.
2.
I rearranged them so the program would make sense by arranging the interaction in a logical order then placing input statements in between
Answer:
no i can't do better ggs
Explanation:
im not smart (also I did answer the question ;) )
Answer:
def recursive_func():
x = input("Are we there yet?")
if x.casefold() == 'Yes'.casefold():
return
else:
recursive_func()
recursive_func()
Explanation:
We define the required function as recursive_func().
The first line takes user input. The user input is stored in variable x.
The next line compares the user input to a string yes. The function executes the else block if the condition isn't met, that is a recursive call is executed.
IF condition returns the function. The string in variable X is compared to a string 'Yes'. the casefold() is a string function that ignores the upper/lower cases when comparing two strings. (This is important because a string 'yes' is not the same yes a string 'Yes' or 'YES'. Two equal strings means their cases and length should match).
