Answer:
12.5% in prophase
Explanation:
We get 69.6 % cells in interphase, 12.5% in prophase, 8.9% in metaphase, 5.4% in anaphase, and 3.6% in telophase.
<span>a.
</span>The frequency of the dominant allele: ___0.4______
<span>b.
</span>The frequency of the recessive allele: ____0.6_____
<span>c.
</span>The percentage of mice that are homozygous
dominant: __16%_______
<span>d.
</span> The
percentage of mice that are heterozygous: _48%________
<span>e.
</span>The percentage of mice that are homozygous
recessive: __36%_______
Let us assign the dominant allele (that of brown hair) letter R
while
We assign the recessive
allele (that of white hair) letter r
We then note down the
Hardy-Weinburg equation p2 + 2pq + q2 = 1
Brown fur population (p2
+ 2pq) = 64% = 0.64
White fur population (q2) = 36% = 0.36
Then we also remember that the frequencies of both allele
add up to 1 (p + q = 1);
Therefore q = ü.36
= 0.6
P = 1 – q = 1 – 0.6 = 0.4
The heterozygous population will be 2*0.6*0.4 = 0.48 = 48%
Homozygous domain population will therefore be (64% - 48%) =
16%
they aren't decomposes or producers
obviously we'd know that
so the remaining options are
primary and secondary consumers
these rabbits and deer, coyotes
are the primary consumers
so, this lion is the secondary consumer
which is option A
Then the submerged aquatic plants will note be able to receive light for photosynthesis. then those submerged aquatic plants will not have food/nutrients to survive, hence die. aquatic animals will not receive sufficient oxygen from those submerged aquatic plants, hence die also.
decomposes will breakdown all dead organisms to release carbon dioxide, and also deplete oxygen concentration during decomposition process.
eventually, habitat is rendered not livable. only the algae continue to proliferate uncontrollably at the water body surface.
Answer: B
Explanation: The other answers are talking about similarities among different species.