X is 35. 180=75+3x. 180-75/3=35
The picture is not clear. let me assume
y = (x^4)ln(x^3)
product rule :
d f(x)g(x) = f(x) dg(x) + g(x) df(x)
dy/dx = (x^4)d[ln(x^3)/dx] + d[(x^4)/dx] ln(x^3)
= (x^4)d[ln(x^3)/dx] + 4(x^3) ln(x^3)
look at d[ln(x^3)/dx]
d[ln(x^3)/dx]
= d[ln(x^3)/dx][d(x^3)/d(x^3)]
= d[ln(x^3)/d(x^3)][d(x^3)/dx]
= [1/(x^3)][3x^2] = 3/x
... chain rule (in detail)
end up with
dy/dx = (x^4)[3/x] + 4(x^3) ln(x^3)
= x^3[3 + 4ln(x^3)]
Answer:
Y = 2
X = 3
Step-by-step explanation:
Substitution:
6(4y-5) - y = 16
24y-30-y=16
23y=46
Y = 2
So then:
6x-2 = 16
6x = 18
X = 3
Answer:
yesss it makes sense!!!!!!!!!!!
Answer:
$1.25
September
$30
Step-by-step explanation:
Let's take this a step a time.
First we need to find how much the price of the flowers were in September.
We know that each flower cost $1.50 on October.
The October price was a 20% increase of the September price.
To calculate for the price of the flowers on September, we can solve it like this:
Let x = Price during September
1.2x = 1.50
We used 1.2 because the price of $1.50 is 120% of the original price.
Now we divide both sides by 1.2 to find x.

x = 1.25
The price of the flowers during September was $1.25 each.
Now the 7th grade class earned 40% of the selling price of each flower.
40% = 0.40
To find how much they made on each month, we simply multiply the percentage to the price and the number of flowers sold.
September = 0.40 x 1.25 x 900
September = 0.5 x 900
September = $450
Now for October.
October = 0.40 x 1.50 x 700
October = 0.6 x 700
October = $420
The 7th Graders earned more on September.
They earned $30 more on September than October.