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docker41 [41]
3 years ago
6

Write an equation for a line perpendicular to y=5x+2 and passing through the point (-5,5)

Mathematics
1 answer:
vodka [1.7K]3 years ago
3 0
Kekejsdssssnmsksjebsbsbfjxjeobtidixpsnvrodnxvsujensksjsjsisjsjsjsjs
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What are the domain values for the function f(x) = 2x + 3 if the range values are (-1, 1, 2,4}
ArbitrLikvidat [17]

Answer:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.

So i think it will be -1

7 0
3 years ago
What is the area of this figure?
goldfiish [28.3K]

Answer:

693

Step-by-step explanation:

7 x 9 x 11 =693

7 0
4 years ago
A sector whose central angle measures 1200 has an area of 12 square inches. What
Verdich [7]

This question is not correctly written

Correct Question

A sector whose central angle measures 120° has an area of 12 square inches. What is the radius of the circle?

Answer:

Radius of the circle = 3.3851375013 inches

Approximately to one decimal place, radius of the circle = 3.4 inches

Step-by-step explanation:

The formula for the area of a sector is given as:

Area of a sector = θ × π/360 × r²

θ = Central angle in degrees = 120°

Area of a sector = 12 in²

12 = (120° × π)/360 × r²

r² = 12 ÷(120° × π)/360

r² = 12 ÷ 1.0471975512

r² = 11.459178217

r = √11.459178217

r = 3.3851375013 inches

Approximately to one decimal place, radius of the circle = 3.4 inches

7 0
3 years ago
Solve for w 5w + 9z = 2z + 3w
Mazyrski [523]

5w + 9z = 2z + 3w \\ 5w - 3w = 2z - 9z \\ 2w =  - 7z \\ w =  \frac{ - 7z}{2}
The answer is w = -7z/2
4 0
4 years ago
Read 2 more answers
Solve for y.<br><br> 8(y – 2) = 4y
Arte-miy333 [17]

Answer:

y =4

Step-by-step explanation:

8(y – 2) = 4y

Distribute

8y -16 =4y

Subtract 8y from each side

8y-8y -16 = 4y -8y

-16 = -4y

Divide each side by -4

-16/-4 = -4y/-4

4 = y

7 0
3 years ago
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