We have 4 apples, 3 peaches, and 4 pears.
The sample size is 11.
1st selection: apple
The probability of selecting an apple is 4/11.
2nd selection: peach
We now have a sample size of 10, which consists of 3 apples, 3 peaches, and 4 pears.
The probability of selecting a peach is 3/10.
3rd selection: peach
We now have a sample size of 9, which consists of 3 apples, 2 peaches, and 4 pears.
The probability of selecting a peach is 2/9.
Each selection was an independent event. Therefore the overall probability is
(4/11)*(3/10)*(2/9) = 4/165
Answer:
The probability of selecting an apple followed by 2 peaches is 4/165.
This probability is equivalent to 0.024 or 2.4%.
Answer:
18
Step-by-step explanation:
6+6+3+3=18
Please Brainliest!!!
It should be 3x^2y
I'm using 3 from numbers because 3 is a GCF of 18 and 15
Then I'm getting X^2 because it's the GCF of X^2 and X^3
Then I'm taking y because it's the GCF of y^3 and y
And finally we got no z on the left side so we get 3x^2y
The first picture is for number 1 and the second one for number 2.
Answer:
x=2
Step-by-step explanation:
3^2x = 81
3^2x = 3^4
Compare powers
2x = 4
x = 2
