<h3>
Hello there today we will solve your problem</h3>
here is our equation,
,
Now we will plug in our numbers
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simplify it and we get



Answer:
Please find attached the drawing of quadrilateral KLMN created with MS Whiteboard using the Ink to Shape command
(a) Two pairs of opposite sides are
,
and
,
(b) Two pairs of opposite angles are ∠LKN, ∠LMN, and ∠KLM and ∠KNM
(c) Two pairs of adjacent sides are
,
and
, 
(d) Two pairs of adjacent angles are ∠LKN, ∠KLM and ∠LMN, ∠KNM
Step-by-step explanation:
We use P = i•e^rt for exponential population growth, where P = end population, i = initial population, r = rate, and t = time
P = 2•i = 2•15 = 30, so 30 = 15 [e^(r•1)],
or 30/15 = 2 = e^(r)
ln 2 = ln (e^r)
.693 = r•(ln e), ln e = 1, so r = .693
Now that we have our doubling rate of .693, we can use that r and our t as the 12th hour is t=11, because there are 11 more hours at the end of that first hour
So our initial population is again 15, and P = i•e^rt
P = 15•e^(.693×11) = 15•e^(7.624)
P = 15•2046.94 = 30,704