Question

A basket contains four apples, three peaches, and four pears. You randomly select and eat three pieces of fruit. The first piece of fruit is an apple and the next two pieces are peaches. Find the probability of this occuring.

Answer 1

We have 4 apples, 3 peaches, and  4 pears.
The sample size is 11.

1st selection: apple
The probability of selecting an apple is 4/11.

2nd selection: peach
We now have a sample size of 10, which consists of 3 apples, 3 peaches, and 4 pears.
The probability of selecting a peach is 3/10.

3rd selection: peach
We now have a sample size of 9, which consists of 3 apples, 2 peaches, and 4 pears.
The probability of selecting a peach is 2/9.

Each selection was an independent event. Therefore the overall probability is
(4/11)*(3/10)*(2/9) = 4/165

Answer:
The probability of selecting an apple followed by 2 peaches is 4/165.
 This probability is equivalent to 0.024 or 2.4%.

Answer 2

Answer:

6/10

Step-by-step explanation: