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natta225 [31]
3 years ago
8

What is the answer, what are the steps to solve this, and what do the parts of the equation represent?

Mathematics
1 answer:
beks73 [17]3 years ago
3 0

Step-by-step explanation:

Just sub 4 into where n is

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The function g(t) = - 16t2 + vt + h represents the height of an object, g, in feet, above the ground in relation to the time, t,
timurjin [86]

Answer:

g(t) = -16t^2+80t.

Step-by-step explanation:

We are given that v=80 and h=0 (because that's the ground), so substituting that into g(t) = -16t^2+vt+h gives g(t) = -16t^2+80t.

5 0
3 years ago
Read 2 more answers
What is the product of a positive number and a negative number?
Natali5045456 [20]
Negative

basically
negative means change sign
positive means do nothing

change sign times do nothing=change sign=negative

basically
(+)(+)=(+)
(-)(-)=(-)
(+)(-)=(-)
(-)(+)=(-)
and

(+)/(+)=(+)
(-)/(-)=(-)
(+)/(-)=(-)
(-)/(+)=(-)

answer is negative

5 0
3 years ago
Help me plz i’m posting rn
nordsb [41]

Answer:

y = 7

Step-by-step explanation:

3y+9 = 2y+16, subtract 9 from both sides, 3y = 2y + 7, then subtract 2y from both sides, y = 7, and that's the answer

3 0
3 years ago
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A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 8​% will need repairs​
Sladkaya [172]

Answer:

Probability that a car need to be repaired​ once = 20% = 0.20

Probability that a car need to be repaired​ twice = 8% = 0.08

Probability that a car need to be repaired​ three or more = 2% = 0.02

a) If you own two​ cars what is the probability that  neither will need​ repair?

Probability that a car need to be repaired​ once , twice and thrice or more= 0.20+0.08+0.02=0.3

Probability that car need no repair = 1-0.3=0.7

Neither car will need repair=0.7 \times 0.7=0.49

​b) both will need​ repair?

Probability both will need​ repair = 0.3 \times 0.3=0.09

c)at least one car will need​ repair

Neither car will need repair=0.7 \times 0.7=0.49

Probability that at least one car will need​ repair= 1-0.49 = 0.51

6 0
3 years ago
A venue plans to host trucking events regularly throughout the year. The expected revenue from each event is $100,000. The cost
iris [78.8K]

Answer:

The venue has to host 47 events throughout the year

Step-by-step explanation:

Profit:

Profit is revenue subtracted by costs.

Per event:

$100,000 revenue

$50,000 costs

$100,000 - $50,000 = $50,000 profit.

If the venue wants to make a total profit margin of $2,350,000, how many events does the venue have to host throughout the year?

1 event - $50,000 profit.

x events - $2,350,000 profit.

50000x = 2350000

x = \frac{2350000}{50000}

x = 47

The venue has to host 47 events throughout the year

6 0
3 years ago
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