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3 years ago

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The invention of the telegraph ______________ a. let distant locations communicate quickly. b. kept distant locations from commu

nicating quickly. c. was 50 years after the railroad. d. was 50 years before the railroad.

1 answer:

VashaNatasha [74]3 years ago

5 0

The answer is a.......

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Quadrilateral ABCD ABCD is similar to quadrilateral EFGH EFGH. The lengths of the three longest sides in quadrilateral ABCD ABCD

Kay [80]

Sketch the two quadrilaterals and label them as shown in the figure below.

Let x = length of the 4th side of ABCD.

Because ABCD ~ EFGH, therefore
x/5 = 14/6

That is,
x = (5/6)*14 = 11.67 ft

Answer: D. 11.7 ft

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4 years ago

I need help im desperate i'll give 30 points to anyone who answers.

Ivahew [28]

Anything that adds up to 12 has to go in the parethese.

48 / 4 = 12

So 1 and 11

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3 years ago

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Determine g(-1) for g(t)=(t^2-1)(t+4) <br><br> A)-2<br> B)-6<br> C)3<br> D)0

Zanzabum

D option that is 0 will be answer

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3 years ago

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N=4; 2i and 3i are zeros <br> f(-1)=50

Nonamiya [84]

Solution:- $\text{Let f(x) be any nth degree polynomial with n=4}\\$

$\text{Given that 2i and 3i are the zeroes of f(x)}$

$\text{so (x-2i) and (x-3i) are factors of f(x)}$

$\text{Since 2i is a zero of f(x) then its conjugate -2i is also a zero of f(x)}$

$\Rightarrow(x+2i) \text{is a factor}\\\text{Similarly, conjugate of 3i is -3i is also a zero of f(x) }\\\Rightarrow(x+3i)\text{is a factor}\\\text{So , }\\f(x)=k(x-2i)(x+2i)(x-3i)(x+3i)\\=k(x^2-(2i)^2)(x^2-(3i)^2)\\=k(x^2-4i^2)(x^2-9i^2)\\=k(x^2+4)(x^2+9)\\=k(x^4+13x^2+36)\\\text{As given}\\f(-1)=50\\\Rightarrow k((-1)^4+13(-1)^2+36)=50\\\Rightarrow k(1+13+36)=50\\\Rightarrow k(50)=50\\\Rightarrow k=1\\\text{So by substituting k=1 in f(x) we get ,}\\f(x)=(x^4+13x^2+36)$

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3 years ago

The sum of a number and 2 times its reciprocal is -3

Marysya12 [62]

Answer:

(-2,-1)

Step-by-step explanation:

let the number=x

its reciprocal=1/x

x+2(1/x)=-3

x+2/x=-3

x²+2=-3x

x²+3x+2=0

(x+2)(x+1)=0

x=-2,-1

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3 years ago