Answer:
Hello some parts of your question is missing below is the missing part
answer : A) p-value = 0.0019 ,
The level of significance ( 0.05 ) > p-value ( 0.0019 )
B) There is no dependence between the two ratings
Step-by-step explanation:
A) using a 0.05 level of significance and test for independence of the quality of management
Test statistic : 
∑ ( Oi - Ei )^2 / Ei
= [(40-35)^2 / 35 ] + [(25-24.5)^2 / 24.5 ] + [(5-10.5)^2 / 10.5] + [(35-40)^2 / 40] + [(35-28)^2 / 28] + [(10-12)^2 / 12] + [ (25-25)^2 / 25 ] + [(10-17.5)^2 / 17.5 ] + [(15-7.5)^2 / 7.5] = 17.03
p-value = 0.0019
Df = 4 ,
The level of significance ( 0.05 ) > p-value ( 0.0019 )
B) There is no dependence between the two ratings
Answer:
x = -4 ± 2√3
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that the population of a city increased steadily over a ten-year span. The following ordered pairs show the population x and the year y over the ten-year span in the form (x, y) for specific recorded years.
x y
2500 2001
2650 2002
3000 2004
3500 2007
4200 2011
Slope 0.005865485
Intercept 1986.406413
So regression line is
When population = 15000
Answer:
Im thinking it is 50
Step-by-step explanation:
Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
