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alexira [117]
1 year ago
11

The sum of two numbers is 48.the second number is seven times the first number​

Mathematics
2 answers:
dusya [7]1 year ago
6 0

Answer:

\huge\boxed{\sf x =6,\ y = 42}

Step-by-step explanation:

Let the numbers be x and y

<h3>Given condition:</h3>

x + y = 48 --------(1)

y = 7x -------------(2)

Put Eq. (2) in (1)

x + 7x = 48

8x = 48

Divide 8 to both sides

x = 48/8

<h3>x = 6</h3>

Put x = 6 in Eq. (2)

y = 7 (6)

<h3>y = 42</h3>

\rule[225]{225}{2}

Mariana [72]1 year ago
4 0

Assume a is the 1st number and b is the 2nd number, a + b = 48

<em>b = 7a</em> (the second number is seven times the first number​)

<em>a = a</em>

So, equation:<em> </em>a + 7a = 48

<em>a + 7a = 48</em>

<em>8a = 48</em>

a = 6

To find b = <em>7 (6)</em> = 42

Hope it helps!

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