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4 years ago

A square has an area of 25 yd . What is the length of each side? in yd

Mathematics

2 answers:

Lady_Fox [76]4 years ago

7 0

Answer:

The side length is 5 yds

Step-by-step explanation:

The area of a square is given by

A = s^2 where s is the side length

25 = s^2

Take the square root of each side

sqrt(25) = sqrt(s^2)

5 = s

The side length is 5 yds

Marysya12 [62]4 years ago

6 0

Answer:

The length is 5 yd.

Step-by-step explanation:

A square has 4 equal sides, so that means their all the same.

The formula for the area of a square is $a^{2} =A$ .

Insert 25 to A. This gives you $a^{2} =25$ .

Now, what two numbers(that are the same) give you 25 when you multiply?

5 is the answer. Since this is the square root of 25.

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Based on historical data in Oxnard college, we believe that 37% of freshmen do not visit their counselors regularly. For this ye

slega [8]

Answer:

A sample size of 1031 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

37% of freshmen do not visit their counselors regularly.

This means that $\pi = 0.37$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

You would like to be 98% confident that your estimate is within 3.5% of the true population proportion. How large of a sample size is required?

A sample size of n is required.

n is found when M = 0.035. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.035 = 2.327\sqrt{\frac{0.37*0.63}{n}}$

$0.035\sqrt{n} = 2.327\sqrt{0.37*0.63}$

$\sqrt{n} = \frac{2.327\sqrt{0.37*0.63}}{0.035}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.37*0.63}}{0.035})^2$

$n = 1030.4$

Rounding up:

A sample size of 1031 is required.

4 0

3 years ago

PLEASE HELP divide. (3x-2)(x-4)-(x-4)(6-5x) /(4-x)(8x-1)

8_murik_8 [283]

Answer:

x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

Step-by-step explanation:

Solve for x:

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = 0

Simplify and substitute y = 4 - x.

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = -434 + 257 (4 - x) - 37 (4 - x)^2

= -37 y^2 + 257 y - 434:

-37 y^2 + 257 y - 434 = 0

Divide both sides by -37:

y^2 - (257 y)/37 + 434/37 = 0

Subtract 434/37 from both sides:

y^2 - (257 y)/37 = -434/37

Add 66049/5476 to both sides:

y^2 - (257 y)/37 + 66049/5476 = 1817/5476

Write the left hand side as a square:

(y - 257/74)^2 = 1817/5476

Take the square root of both sides:

y - 257/74 = sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

y = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Substitute back for y = 4 - x:

4 - x = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Subtract 4 from both sides:

-x = sqrt(1817)/74 - 39/74 or y - 257/74 = -sqrt(1817)/74

Multiply both sides by -1:

x = 39/74 - sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

x = 39/74 - sqrt(1817)/74 or y = 257/74 - sqrt(1817)/74

Substitute back for y = 4 - x:

x = 39/74 - sqrt(1817)/74 or 4 - x = 257/74 - sqrt(1817)/74

Subtract 4 from both sides:

x = 39/74 - sqrt(1817)/74 or -x = -39/74 - sqrt(1817)/74

Multiply both sides by -1:

Answer: x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

7 0

3 years ago

The scale is 2cm = 25m. Find the length each measurement ould be on a scale drawing:

balandron [24]

1) 12 cm
2) 38
3) 20
4) 40

Each cm is equivalent to 12.5m. So what you can do I just divide all of them by 12.5 to get the answers above.

5 0

4 years ago

Name the property illustrated by the equation.

lawyer [7]

The correct awnser is A.

6 0

3 years ago

Please help me i beg you PLEASE HELP ME ASAP I SWEAR TO GOD WILL MARK YOU BRAINIEST

daser333 [38]

Step-by-step explanation:

DEFINITION: Besting: the clockwise totation (0° to 360°) from North to any line.

A) Calculate the bearings of D from A:

bearings of D from A =x

looking the picture:

x=48°+55°+180°

x+103°+180°

x=283°

B)Calculate the bearings of A from C:

bearings of A from C =y

180°+55°=y

y=235°

C) Calculate the distance between A and B:

The angle in B is 74° (Because 55°+51°+74°=180°)

Using the Law of sines:

$\frac{19}{sin(74)} =\frac{AB}{sin(51)} \\\\AB=19sin(51)sin(74)\\AB=14,2\\\\$

D)Calculate the distance between D and C:

Using the Law of cossines:

$DC^{2} =27^{2} +19^{2} -2*27*19*cos(48)\\DC=20,09$

E) A Helicopter is hovering at A at a height of 2.5Km, find angle of elevation of helicopter from C:

The triangle HBA is rectangle

$\alpha =arctan(\frac{2,5}{19})$

α=7,49°

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3 years ago