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Goryan [66]
3 years ago
9

What are the square roots of 64144 ? −812 and 812 −49 and 49 −3272 and 3272 −412 and 412

Mathematics
1 answer:
worty [1.4K]3 years ago
5 0

Answer:

-8/12 and 8/12

Step-by-step explanation:

I took the test from K12, and that other guy did not help, so here you are! Good luck guys!!!

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Rodent has two 7-foot-long pipes he needs to cut them into pieces that are 15 inches each what is the greatest number of 15 inch
Mice21 [21]
12 inch=1 ft
7 x 12=84 inches
84/15=5.6, so he can cut 5 , 15 inch piecs with .6 left over.
4 0
3 years ago
Drag each tile to the correct location. Each tile can be used more than once, but not all tiles will be used.
AysviL [449]

Answer:

y=770-55x --- given

y - 770 = 770 - 55x - 770 ----subtraction property of equality

y = -55x + 770 ---Simplification

y-770/-55 = -55x/-55 --- Division property of equality

-y-770/55=x---Simplification

Step-by-step explanation:

6 0
3 years ago
Simplify 7-5x-(3+5x)
KatRina [158]

Answer:

4-10x

Step-by-step explanation:

4 0
3 years ago
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
4. HM SENSE-MAKING
meriva

Answer:

15x+55y+20

Step-by-step explanation:

mark me brainlest

7 0
3 years ago
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