Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1
Let us consider the common ratio to be ‘x’.
So, toy blocks with alphabet A is 4x and
toy blocks with alphabet B is 7x and
toy blocks with alphabet C is 3x and
toy blocks with alphabet D is x
Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks.
As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively.
So,
4x=50 + 3x
x=50
Thus, the number of ‘B’ blocks is 7x = 7(50) = 350
350 is the required number.
Answer:
46th term of the sequence is 364
Step-by-step explanation:
first term = 4
common difference = 12 - 4 = 8
46th term = first term+(46 - 1)×common difference
so,
- 46th term = 4 + ( 45 ) × 8
- 46th term = 4 + 360
- 46th term = 364
<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em>
90 or 100 something like that.
Answer:
mhmm
Step-by-step explanation: