Question

Find the vertex of the parabola given by the following equation. y=x^2+10x+33

Answer 1

Answer:

Vertex of the parabola is ( -5 , 8 ).

 

Step-by-step explanation:

Given:

Equation of parabola,

y = x² + 10x + 33

To find: Vertex of the parabola

Vertex form of the parabola is ,

y = a( x - h )² + k

where, ( h , k ) is the vertex of the parabola.

Consider,

y = x² + 10x + 33

y = x² + 10x + 5² - 5² + 33

y = ( x + 5 )² - 25 + 33

y = ( x + 5 )² + 8

by comparing, we get

Vertex is ( -5 , 8 )

Therefore, Vertex of the parabola is ( -5 , 8 )

Answer 2

If you rewrite it as: y = (x+5)^2 + 8

You will see the vertex will be : (-5, 8)