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2 years ago

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Sam and Janet are mountain biking. Sam rides his bike down into a valley, 8 feet below sea level. Janet rides her bike to the to

p of a hill, 437 feet above sea level. What is the vertical distance between Sam and Janet?

1 answer:

Soloha48 [4]2 years ago

6 0

The answer is 429. May not be right. But I am positive it is

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What is the solution to the equation 3 + 4/4y = 4?

Aloiza [94]

Answer:

B. y= ¼

Step-by-step explanation:

3 + ^4√4y = 4

^4√4y =4-3

^4√4y = 1

^4√4y =^4√1

so, 4y = 1

y = ¼

3 0

2 years ago

Represent the amount four tenths in four different ways

aniked [119]

4/10 means 4 tenths (4 times 1/10)
4/10
0.4
2/5
40/100
40%

5 0

3 years ago

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A survey all beings on plant Kent found that 20 beings preferred Freon juice to all other juices. If 50 beings surveyed altogeth

Ugo [173]

Answer: 40%

Step-by-step explanation:

Since 20 beings preferred Freon juice to all other juices and there were 50 people that were surveyed, the percentage of those that preferred Freon Juice will be:

= Those that preferred Freon Juice / Total number surveyed. × 10

= 20/50 × 100

= 40%

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2 years ago

Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

4 0

3 years ago

Leo makes a cake by mixing flour, eggs and sugar in the ratio 5 : 3 : 2. If he uses 120 g of sugar, what weight of eggs will he

Verdich [7]

Answer:

180g of eggs

Step-by-step explanation:

7 0

2 years ago

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