Question

A rectangle’s length is 5 inches more than twice its width. Its area is 50 square inches. Which equation can be used to find its width, w? 2w(2w + 5) = 50 2w(w + 5) = 50 w(2w + 5) = 50 w(w + 5) = 50

Answer 1

For this case we define the following variables:

• L: length of the rectangle
• w: width of the rectangle

We have that by definition, the area of a rectangle is given by:

$A = w * L$

Then, we have that the length is 5 inches more than twice its width:

$L = 2w + 5$

Substituting values we have:

$w (2w + 5) = 50$

Answer:

An equation that can be used to find its width, w is:

$w (2w + 5) = 50$

Answer 2

A=LW
L=5+2W
A=50


50=LW
sub 2W+5 for L
50=(2W+5)W

answer is the 3rd equation