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3 years ago

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In a homicide case 6 different witnesses picked the same man from a line up. The line-up contained 5 men. If the identifications

were made by random guesses, find the probability that all 6 witnesses would pick the same person. Round your answer to 5 decimal places.

1 answer:

Vedmedyk [2.9K]3 years ago

6 0

Answer:

since we have 6 witnesses and 5 men so,

therefore the probability that they would pick the same man is $\frac{5}{6} =0.83333$ to 5 decimal places

Step-by-step explanation:

probability is the likelihood of an event occurring or not happening.

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Determine the equation of the line that passes through the points of intersection of the graphs of the quadratic functions f(x)

timofeeve [1]

Answer: $x-2y-2=0$

Step-by-step explanation:

Given :

$f(x) = x^2 - 4 \\ g(x) = - 3x^2 + 2x + 8$

Point of intersection :

$f(x)=g(x)\\x^2-4=-3x^2+2x+8\\4x^2-2x-12=0\\2x^2-x-6=0\\2x^2-4x+3x-6=0\\2x(x-2)+3(x-2)=0\\(x-2)(2x+3)=0\\x=2\,,\,\frac{-3}{2}$

$x=2\,;f(2)=2^2-4=0\\x=\frac{-3}{2}\,; f\left ( \frac{3}{2} \right )=\left ( \frac{3}{2} \right )^2-4=\frac{-7}{4}=-1.75$

So, we have points $\left ( 2,0 \right )\,,\,\left ( -1.5,-1.75\ \right )$

Equation of line passing through two points $\left ( x_1,y_1 \right )\,,\,\left ( x_2,y_2 \right )$ is given by $y-y_1=\frac{y_2-y_1}{x_2-x_1}\left ( x-x_1 \right )$

Let $\left ( x_1,y_1 \right )=\left ( 2,0 \right )\,,\,\left ( x_2,y_2 \right )=\left ( -1.5,-1.75\ \right )$

So, equation is as follows :

$y-0=\frac{-1.75-0}{-1.5-2}\left ( x-2 \right )\\y=\frac{-1.75}{-3.5}\left ( x-2 \right )\\y=\frac{1}{2}(x-2)\\2y=x-2\\x-2y-2=0$

4 0

4 years ago

24/16 in simplist form

bonufazy [111]

1 1/2
Hope I helped! (^_^)/

7 0

4 years ago

Read 2 more answers

Which polynomial function could be represented by the graph below?

Svetllana [295]

Note that

1.

$f(x)=x^3+x^2-6x=x(x^2+x-6)=x(x-2)(x+3)$

The x-intercepts are at points x=-3, x=0, x=2. The graph should be increasing - decreasing - increasing.

2.

$f(x)=x^3-x^2-6x=x(x^2-x-6)=x(x+2)(x-3)$

The x-intercepts are at points x=-2, x=0, x=3. The graph should be increasing - decreasing - increasing.

3.

$f(x)=-2x^3-2x^2+12x=-2x(x^2+x-6)=-2x(x-2)(x+3)$

The x-intercepts are at points x=-3, x=0, x=2. The graph should be decreasing - increasing - decreasing.

4.

$f(x)=-2x^3+x^2+12x=-2x(x^2-x-6)=-2x(x+2)(x-3)$

The x-intercepts are at points x=-2, x=0, x=3. The graph should be decreasing - increasing - decreasing.

From the diagram you can see that x-intercepts are at points x=-3, x=0, x=2 and the graph is decreasing-increasing-decreasing.

Answer: correct choice is 3.

7 0

4 years ago

Read 2 more answers

The total cost, y, for Leah and x friends to go to an amusement park can be modeled by a

Katarina [22]

Answer:

Range of the function is:

{55.25, 100.50, 145.75, 191.00, 236.25, 281.50}

Step-by-step explanation:

Given that:

Seating capacity of the car = 6

Entrance fee per person = $45.25

Parking fee per car = $10

Leah is accompanied by $x$ friends.

So, the total cost can be modeled as the following linear function:

$y=45.25x+10$

Now, the value of $x$ i.e. number of friends going with Leah can be any of the following:

0, 1, 2, 3, 4 or 5 (because maximum capacity of the car is 6).

Leah is also going.

So, total number of people can be 1, 2, 3, 4, 5 or 6.

Therefore, the table of $x, y$ can be:

$\begin{center}\begin{tabular}{ c c}x & y \\ 1 & 55.25 \\ 2 & 100.50 \\ 3 & 145.75 \\ 4 & 191 \\ 5 & 236.5 \\ 6 & 281.50 \\\end{tabular}\end{center}$

Here, the value of $y$ is nothing but the range of the function.

Therefore, the range of the linear function is:

{55.25, 100.50, 145.75, 191.00, 236.25, 281.50}

7 0

3 years ago

Which expression both gives the average rate of change of the function h(x)

liubo4ka [24]

Answer:

D

Step-by-step explanation:

The average rate of change of a function over an interval a ≤ x ≤ b is found by:

$\frac{f(b)-f(a)}{b-a}$

Here, a is 0 and b is 3, so: $\frac{f(3)-f(0)}{3-0}=\frac{f(3)-f(0)}{3}$

Just plug in 3 for the first term and 0 for the second term in the numerator:

- First term: $\frac{1}{2} (3^{3+\frac{1}{2} })+3=\frac{1}{2} (3^{3\frac{1}{2} })+3$

- Second term: $\frac{1}{2} (3^{0+\frac{1}{2} })+3=\frac{1}{2} (3^{\frac{1}{2} })+3$

So, the final answer is:

$\frac{[\frac{1}{2} (3^{3\frac{1}{2} })+3]-[\frac{1}{2} (3^{\frac{1}{2} })+3]}{3}$

Thus, the answer is D.

Hope this helps!

5 0

3 years ago