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3 years ago

if two parents whose blood types are both B produce a child that has blood type O, what can you say about the parents genotype?

1 answer:

6 0

Both parents would have to be heterozygous. Their genotypes would be either BO and BO, or IBi and IBi.
(Each parent has one B allele, and one O or 'no antigen' allele.)

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Which of the following research questions would be the most appropriate selection for a student studying acids and bases?

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C. How does the interaction of acids and bases relate to the cleaning products industry?

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3 years ago

In a healthy eukaryotic cell, the rate of DNA repair is typically equal to the rate of DNA mutation. When the rate of repair lag

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When the rate of repair lags behind the rate of mutation, the possible fate of the cell is that (A) The cell can be transformed into a cancerous cell.

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2 years ago

Anemia is a medical condition in which the affected person lacks enough red blood cells. What two effects will such a condition

salantis [7]

a)The patient will have less hemoglobin in the blood. (Hemoglobin is carried in red blood cells)
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8 0

3 years ago

Read 2 more answers

Assume a population of purple and white flower pea plants (2000 total plants) is in Hardy-Weinberg equilibrium. The frequency of

lys-0071 [83]

Answer:

a) $0.48$

$p= 0.4\\q=0.6$

c) $720$

Explanation:

Given ,

Frequency of white flower plant ( $p^2$ ) is $0.16$

Thus, frequency of dominant white allele ( $p$ ) is equal to $\sqrt{0.16} \\= 0.4$

As we that, as per Hardy-Weinberg equilibrium equation

$p+q=1$

Substituting the value of $p$ in above equation, we get

$0.4+q=1\\q=1-0.4\\q=0.6$

a) As per Hardy-Weinberg equilibrium equation

$p^2+q^2+2pq=1\\$

Substituting the given and calculated values in above equation, we get -

$0.4^2+0.6^2+2pq=1\\0.16+0.36+2pq=1\\2pq=1-0.16-0.36\\2pq=0.48$

b) The frequency (decimal form) of the dominant allele

$p= 0.4\\q=0.6$

c) number of homozygous purple flower plants

$=$ frequency of purple flower plants ( $q^2$ ) $*$ Number of flowers

$= q^2 * 2000\\= (0.6^2)*2000\\= 0.36 * 2000\\= 720$

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3 years ago

Doubling of plasma sodium concentration be a reasonable approximation of plasma osmolality?

harkovskaia [24]

No. The doubling of sodium accounts for the negative ions associated with sodium and the exclusion of potassium approximately allows for the incomplete dissociation of sodium chloride. Osmolarity is the calculation of the osmolar convergence of plasma and is corresponding to the quantity of particles per liter of arrangement; it is communicated as mmol/L. This is what is utilized when a figured esteem is inferred.

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3 years ago