We can parameterize this part of the cylinder using

with

and

. Then the surface element is


so the area is given by the surface integral, where

denotes the part of the cylinder in question,

Probably less work would involve a simpler geometric approach, but it doesn't hurt to practice setting up a proper surface integral.
Answer:
1
Step-by-step explanation:
1) first, we need to calculate slope of old line:
Let’s take coordinate points (3,7) and (4,9)
3-x1
7-y1
4-x2
9-y2
Slope formula: (y2-y1)/(x2-x1)
Let’s plug in our values:
(9-7)/(4-3)
2/1
Old slope=2
So we need to divide 2 with 2
2/2=1
New slope=1
Hope this helps
Answer:
<em>A. 35 deg</em>
Step-by-step explanation:
The triangles are congruent bu HL.
m<RCD = m<PCD = 35 deg
4y^2 + 2 - 2 = 38 - 2 (subtract both side by 2)
4y^2 = 36
Divide by 4:
y^2 = 9
y = 
y = 3