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telo118 [61]
2 years ago
12

Find the solution to the system of equations. x + y + z = 25 y+z= 18 Z= 7

Mathematics
1 answer:
Umnica [9.8K]2 years ago
6 0

Answer:

x=7

y=11

z=7

Step-by-step explanation:

x + y + z = 25

y+z= 18

Z= 7

Substitute the third equation into the second

y+z=18

y+7 = 18

y = 18-7

y = 11

Now substitute y=11 and z=7 into the first

x +y+z = 25

x+11+7 = 25

x+18 = 25

x = 25-18

x=7

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The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term
Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be 1, 5, and 25.

The sum of the first seven terms of the geometric sequence would be 127.

Step-by-step explanation:

<h3>1.</h3>

Let d denote the common difference of the arithmetic sequence.

Let a_1 denote the first term of the arithmetic sequence. The expression for the nth term of this sequence (where n\! is a positive whole number) would be (a_1 + (n - 1)\, d).

The question states that the first term of this arithmetic sequence is a_1 = 1. Hence:

  • The third term of this arithmetic sequence would be a_1 + (3 - 1)\, d = 1 + 2\, d.
  • The thirteenth term of would be a_1 + (13 - 1)\, d = 1 + 12\, d.

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let r denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d.

Ratio between the third term and the second term of the geometric sequence:

\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}.

Both (1 + 2\, d) and \left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right) are expressions for r, the common ratio of this geometric sequence. Hence, equate these two expressions and solve for d, the common difference of this arithmetic sequence.

\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}.

(1 + 2\, d)^{2} = 1 + 12\, d.

d = 2.

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be 1, (1 + (3 - 1) \times 2) = 5, and (1 + (13 - 1) \times 2) = 25, respectively.

These three terms (1, 5, and 25, respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be r = 25 /5 = 5.

<h3>2.</h3>

Let a_1 and r denote the first term and the common ratio of a geometric sequence. The sum of the first n terms would be:

\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}.

For the geometric sequence in this question, a_1 = 1 and r = 25 / 5 = 5.

Hence, the sum of the first n = 7 terms of this geometric sequence would be:

\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}.

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The answer would be 2.
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Simplify x^2-9x-22/x-11
OleMash [197]

Answer:

x^2-11/-8x

Step-by-step explanation:

We can solve this equation easily by using PEMDAS, or order of operations.

<u>Parenthesis</u>

<u>Exponents</u>

<u>Multiplication>Division (Depends on which comes first left to right)</u>

<u>Addition>Subtraction (See multiplication>division)</u>

Now that we know the order of the operations, we can solve.

First, we cant solve for x^2 because we dont know the value of x, so well leave that alone. Same with 22/x. All we can do is use the commutative property.

So our equation is now x^2-11/-8x

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