All categories

3 years ago

PLZ HELP ME AGAIN! What is the solution to the following equation? 4(3x − 6) + 15 = 27

Mathematics

2 answers:

Svet_ta [14]3 years ago

4 0

Solutions

$4(3x-6)=27-15$

$4(3x-6)=12$

$3x-6= 12 / 4$

$3x-6=3$

$3x=3+6$

$3x=9$

$x= 9 / 3$

$x=3$

Hence Solved

Lyrx [107]3 years ago

3 0

12x - 24 + 15 = 27

12x - 24 = 12

12x = 36

36 / 12 = 3

x = 3

Hope this helps!

You might be interested in

The graph of a function is shown below. Which ordered pair best represents the location of the y intercept

Wittaler [7]

When a question is asking you for the y-intercept based on a graph, all you have to do is look to see at what point does the function cross/intersect the y-axis. The x-value will always be zero in a y-intercept. By looking at the graph you see that the function crosses the y-axis at the point (0, -1), which is your answer.

Answer: (0, -1)

8 0

3 years ago

The prism shown has a volume of 35 cm^3

artcher [175]

Answer:

$Height = 2.5$

Step-by-step explanation:

Given

$Volume = 35$

$Length =7$

$Base=4 cm$

Required

Determine the height

The volume is calculated as:

$Volume = Height * Base\ Area$

Since, it has a triangular cross-section, the expression becomes:

$Volume = Height * \frac{1}{2} * Base * Length$

So, we have:

$35 = Height * \frac{1}{2} * 4 * 7$

$35 = Height * 14$

$Height = 35/14$

$Height = 2.5$

7 0

3 years ago

Someone help ASAP please !! I’ll vote Brainliest !

alukav5142 [94]

Answer:

Step-by-step explanation:

The y-intercept corresponds to the ordered pair having an x-value of 0. The second row of the table has an x-value of 0, and y-value of 2. Therefore, the y-intercept is (0, 2).

6 0

2 years ago

Simplify (square root 2)( square root of 2^3)

steposvetlana [31]

Answer:

$\large\boxed{(\sqrt2)(\sqrt{2^3})=4}$

Step-by-step explanation:

$(\sqrt2)(\sqrt{2^3})\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt{2\cdot2^3}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{2^{1+3}}=\sqrt{2^4}\\\\(1)=\sqrt{2^{2\cdot2}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(2^2)^2}\qquad\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=2^2=4\\\\(2)=\sqrt{2\cdot2\cdot2\cdot2}=\sqrt{16}=6\ \text{because}\ 4^2=16$

8 0

3 years ago

Can you help me solve that

yuradex [85]

Answer:2.6

Step-by-step explanation:

Use your graphing calculator of you have one and if you don't you can find one online and plug in the equation and find the intersection . If you get 2.5571 round it to the nearest tenth and you should get 2.6

6 0

3 years ago

Read 2 more answers