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2 years ago

keisha drove 225 miles using 10 gallons of gas. at this rate, how many gallons of gas would she need to drive 441 miles

Mathematics

1 answer:

Contact [7]2 years ago

5 0

225miles=10 gallons what about 441 miles
441 x10 divided by 225
=19.6 gallons

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Write and solve the equations. A number y is five less than thirteen.

Genrish500 [490]

We can follow the following steps to make an equation and solve it.

Step 1:

five less than 13 means we have to subtract 5 from 13

so it becomes 13-5

Step 2:

A number y is five less than thirteen.

Now in algebraic expressions, "is" stands for "="

So we have:

$y=13-5$

Step 3:

Solving the equation to find y.

$y=13-5$

Subtracting 5 from 13, we get :

y=8

Answer:

For the given equation the solution is y=8.

4 0

2 years ago

Subtract 7x-9 from2x^2-11

strojnjashka [21]

Answer:

The answer is: $2x^2-7x-2$

Step-by-step explanation:

we are asked to subtract $7x-9$ from $2x^2-11$

so, $2x^2-11-(7x-9)\\=2x^2-11-7x+9\\=2x^2-7x-2$ .

Hence the desired result is: $2x^2-7x-2$ .

8 0

2 years ago

Read 2 more answers

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

2 years ago

Find missing angleeeeeeeeeeeeeeeeeeeeeeee

dimulka [17.4K]

Answer:

C) 80

Step-by-step explanation:

triangles always add up to 180 degrees, so 80+20=100 the missing angle is 80 degrees

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2 years ago

Find the equation of the line that is parallel to the

zepelin [54]

9514 1404 393

Answer:

y = -x -12

Step-by-step explanation:

The slope of the line you want is the same as the slope of the line you have: -1. Then the point-slope equation of the line is ...

y -k = m(x -h) . . . . . . line of slope m through point (h, k)

y -(-7) = -1(x -(-5))

y = -x -5 -7 . . . . subtract 7, eliminate parentheses

y = -x -12 . . . slope-intercept equation

6 0

2 years ago