trent added water to a pool. It took 3 minutes to add 9 gallons of water How long would it take to add 18 gallons of water to th
2 answers:
It would take 6 minutes to add 18 gallons of water in the pool
Step-by-step explanation:
Trent added water to a pool.
- It took 3 minutes to add 9 gallons of water
- We need to find how long it would take to add 18 gallons of water to the pool
Let us find the time needs to add one gallon in the pool
∵ It took 3 minutes to add 9 gallons
- Divide the time by the number of gallons
∴ Time to add 1 gallon = 3 ÷ 9 =
∴ It took minutes to add 1 gallon
We need the time to added 18 gallons multiply the time of 1 gallon
by the numbers of gallons
∵ Time per gallon =
∵ The number of gallons = 18
∴ The time to add 18 gallons = × 18
∴ The time to add 18 gallons = 6 minutes
It would take 6 minutes to add 18 gallons of water in the pool
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Answer:
Step-by-step explanation:
Step 1:
x - > number of Avocado
y -> number of melon
Step 2:
x ≤ 3y
x + y ≥ 20
Step 3:
x + y≥ 20
y ≥ -x + 20
Step 4:
( 1 , 20)
x ≤ 3y ; y≥ -x + 20
1 ≤ 3*20 ; 20 ≥ -1 + 20
1 ≤ 60 ; 20 ≥ 19
Answer:
a) 59.98
b) 2.99
c) 2.99
d) Significantly High
Step-by-step explanation:
Part a)
Highest speed measured = x = 75.6 Mbps
Average/Mean speed = = 15.62 Mbps
Standard Deviation = s = 20.03 Mbps
We need to find the difference between carrier's highest data speed and the mean of all 50 data speeds i.e. x -
x - = 75.6 - 15.62 = 59.98 Mbps
Thus, the difference between carrier's highest data speed and the mean of all 50 data speeds is 59.98 Mbps
Part b)
In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.
This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.
Part c)
A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:
The formula for the z score is:
Using the given values, we get:
Thus, the Carriers highest data is equivalent to a z score of 2.99
Part d)
The range of z scores which are neither significantly low nor significantly high is -2 to + 2. The z scores outside this range will be significant.
Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the carrier's highest data speed is significantly higher.