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worty [1.4K]
3 years ago
11

The 2017 population of California was 39536653 and of Arizona was 7016270. Compute and compare the rate of pedestrian fatalities

per 100,000 residents.
Mathematics
1 answer:
jasenka [17]3 years ago
6 0

Answer:

The pedestrian fatality rate for California per 100,000 residents would be;

= (858/39,536,653) * 100,000

= 2.17 people per 100,000

In Arizona that figure is;

= (216/7,016,270) * 100,000

= 3.08 people per 100,000

<em>This shows that even though California has a higher number of pedestrian fatalities in absolute terms, when this figure is made relative to population, Arizona has more pedestrian fatalities. </em>

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Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

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Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

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And we have;

\mu_{\bar X}= 14.70

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Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of \bar X Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

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Part B:

The number of minutes Eric spends playing volleyball each day is 35 minutes

Part C:

It is not possible for Eric to have spent exactly 35 minutes playing basketball

Step-by-step explanation:

The total time Eric plays basketball and volleyball = 95 minutes

The time duration Eric plays basket ball = x

The time duration Eric plays volleyball = y

Part A:

The pair of relationships between the number of minutes Eric plays basketball (x) and the number of minutes he plays volleyball (y) are;

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By substituting the value of x in equation (2) into equation (1), we have;

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It is not possible for Eric to have spent only 35 minutes playing basketball because, given that he plays basketball for 25 minutes longer than he plays volley, the number of minutes he spends playing volleyball will then be given as follows;

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35 = y + 25

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The total time = x + y = 10 + 35 = 45 minutes ≠ 95 minutes.

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