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trapecia [35]
3 years ago
6

Write ordered pairs of integers that satisfy the criteria in each part below. Remember that the origin is the point whose coordi

nates are (0, 0). When possible, give ordered pairs such that (i) both coordinates are positive, (ii) both coordinates are negative, and (iii) the coordinates have opposite signs in either order.
a. These points’ vertical distance from the origin is twice their horizontal distance.
b. These points’ horizontal distance from the origin is two units more than the vertical distance.
c. These points’ horizontal and vertical distances from the origin are equal, but only one coordinate is positive.
Mathematics
1 answer:
enot [183]3 years ago
5 0

Answer:

a. These points’ vertical distance from the origin is twice their horizontal distance.

both coordinates positive A(2,4)

both coordinates negative B (-2,-4)

opposite signs case 1:  C (2,-4)

opposite signs case 2: D (-2,4)

b. These points’ horizontal distance from the origin is two units more than the vertical distance

both coordinates positive A(4,2)

both coordinates negative B (-4,-2)

opposite signs case 1:  C (4,-2)

opposite signs case 2: D (-4,2)

c. These points’ horizontal and vertical distances from the origin are equal, but only one coordinate is positive.

Case 1 x coordinate negative

A (-5,5)

Case 2 y coordinate negative

B (3,-3)

Step-by-step explanation:

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Use the Law of Sines to find the measure of angle J to the nearest degree.
rjkz [21]
\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-----------------------------\\\\
\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}
\\\\\\
\textit{now taking }sin^{-1}\textit{ to both sides}
\\\\\\
sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
\\\\\\
\measuredangle J=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
8 0
4 years ago
30 POINTS!
inessss [21]
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7 0
3 years ago
Please give me the correct answer.​
ANEK [815]
Answer x=1/5
6x-3=-9x
-3=-15x
-3/-15x=1/5
7 0
3 years ago
Please help I with give Brainiest if correct
padilas [110]

Answer:

  Perimeter of the rectangle  = 6 x +20

 Perimeter of the rectangle  = 0<em> x² + 6 x + 20</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the length of the rectangle = 2x +3

Given that the width of the rectangle = x +7

Perimeter of the rectangle   = 2(length + width)

<u>Step(ii):-</u>            

  Perimeter of the rectangle   = 2(length + width)

                                                  = 2(2 x +3 + x+7)

                                                 =  4x +6+2x+14

                                                 = 6 x +20        

<u><em>Final answer:-</em></u>

 Perimeter of the rectangle  = 6 x +20

 Perimeter of the rectangle  = o x² + 6 x + 20

7 0
3 years ago
Check the image for question
Aliun [14]

Answer:        m^5/2a^4

Step-by-step explanation:

There is a theorm that describes this. Search "polynomial division rule" and it should come up.

5 0
3 years ago
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